Timeline for Why does mixing every paint colour produce gray instead of white?
Current License: CC BY-SA 3.0
25 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 14, 2023 at 1:33 | review | Suggested edits | |||
| Oct 14, 2023 at 13:28 | |||||
| Feb 13, 2022 at 5:46 | comment | added | hdhondt | Refraction is when a light ray is bent (as when going through a lens). Reflection is when a light ray bounces off a surface. If you see red light going through glass, that means glass absorbs the other colours. You should really start new questions, instead of using comments to ask additional ones. | |
| Feb 12, 2022 at 12:11 | comment | added | S. M. | @hdhondt suppose incoming light that enters the into any red object then except red everything get absorbed. Then this red light which I see is refraction or reflection light? I seem it's refraction? What is right? | |
| Feb 11, 2022 at 5:18 | comment | added | hdhondt | That is essentially correct. | |
| Feb 11, 2022 at 1:36 | comment | added | S. M. | @hdhondt when white light incident on cyan ink it absorbs red light and reflects green and blue—remember then green + blue light = cyan. My question is it only reflects green and blue light among 7 colors (white light) ? Remaining lights is absorbed like red color? | |
| Feb 11, 2022 at 1:08 | comment | added | hdhondt | @User4567 because the RGB pixels in a monitor produce light, while the CMYK pixels in a print remove light from the illuminating source (e.g. sunlight). | |
| Feb 10, 2022 at 16:34 | comment | added | S. M. | @hdhondt if RGB provides glow, why we need cmyk for printing? I mean why cmyk is efficient for printing than RGB? | |
| Feb 10, 2022 at 4:39 | comment | added | hdhondt | Look at the graph in my link. The outside "triangle" shows the colours the eye can see; the inner triangles show the range of colours various devices can produce. On those devices you will never see the colours outside the device's triangle, as they cannot be produced. | |
| Feb 10, 2022 at 3:49 | comment | added | S. M. | @hdhondt that understand. But you wrote in answer any device which has color we can see but device can't produce? My question is how? | |
| Feb 10, 2022 at 3:45 | comment | added | hdhondt | @User4567 For additive colour you use 3 colours: red, green, and blue. In equal quantities they make white (or grey); in unequal amounts they mix to make the other colours. Look at a TV screen with a magnifier, you'll see nothing but red, green and blue dots. White light or sunlight are not needed - but too much of it will wash out the screen. | |
| Feb 10, 2022 at 3:42 | comment | added | hdhondt | @User4567 Any device has a range of colours it can produce. The eye has a range of colours it can see. Those ranges overlap, but not completely. See, for example, deprintedbox.com/blog/wp-content/uploads/2014/03/… | |
| Feb 10, 2022 at 2:44 | comment | added | S. M. | @hdhondt, SolomonSlow "so with any device there are colours we can see but which the device cannot produce. "----what does mean this statement? Any device which produce the color that we see, but you are saying we see the color which cannot be produced. Didn't understand properly. Please explain little. | |
| Feb 10, 2022 at 2:35 | review | Suggested edits | |||
| Feb 10, 2022 at 3:47 | |||||
| Feb 10, 2022 at 2:08 | comment | added | S. M. | @hdhondt one thing tell to create additive color we need absence of white light or absence of sunlight? | |
| Feb 10, 2022 at 2:07 | comment | added | S. M. | @SolomonSlow one thing tell to create additive color we need absence of white light or absence of sunlight? | |
| Nov 30, 2020 at 7:44 | review | Suggested edits | |||
| Nov 30, 2020 at 8:55 | |||||
| Jul 3, 2015 at 9:46 | comment | added | Solomon Slow | I did not say "white". White is highly subjective. web.mit.edu/persci/people/adelson/checkershadow_illusion.html If you mix red, green, and blue pigments, then the mixture will reflect some red light, some green light, and some blue light. Only a third of the particles will be red, so the mixture will reflect only about a third as much red light as the pure red pigment. Likewise for green and for blue. If you had a card that reflected one third of all light, and you held it up next to another card that reflected, say 95%, you would call the first one "gray." | |
| Jul 3, 2015 at 7:12 | comment | added | hdhondt | @james large: So you're telling me that if I mix red, green and blue paints the resulting colour will be white??? Try it with some real paints. | |
| Jul 1, 2015 at 20:43 | comment | added | Solomon Slow | If you mix paints together you should get black. No, because paints are pigments. Each non-black pigment particle in the mix reflects some fraction of light. The only way the paint could look black (i.e., reflect none of the light) is if all of the particles are black. | |
| Feb 18, 2014 at 16:21 | comment | added | supercat | Simplified color theory works nicely when when combining lights to achieve a certain look, or when combining dyes whose absorption spectra are largely non-overlapping, so as to achieve a certain look under some particular illuminating spectrum. The way materials' colors interact, though, depends upon their behavior at individual wavelengths. I wonder how hard it would be to construct a telescope-like device which would clearly show the spectral content of a spot at the center of the view field, marked with a cross-hairs or other indicator. That could assist understanding of "real" color. | |
| Feb 18, 2014 at 9:36 | comment | added | hdhondt | And then there are metallic paints. There is a huge chasm between colour theory and actual colour work. Hopefully we've given @Hal the incentive to investigate further. | |
| Feb 17, 2014 at 19:58 | comment | added | supercat | ...to get reflected by a red particle first. Since some light that reflects off a red particle will hit (and be absorbed by) a green particle before bouncing clear of the paint, the behavior of mixed paints isn't exactly additive, but it isn't subtractive either. Note that many paints include dyes, which do behave in subtractive fashion; two kinds of "blue" paints may appear identical, but yield very different results when combined with a "yellow" paint. Some kinds of yellow, mixed with true "blue" (not cyan) will yield green--not consistent with additive or subtractive color rules. | |
| Feb 17, 2014 at 19:54 | comment | added | supercat | Combinations of dyes will yield a subtractive color mix, since dye molecules absorb light of some wavelengths while passing others. If one has dye with particles which absorb everything but green, adding particles which absorb everything but red won't help any light get through. Paint, however, often has particles which reflect certain wavelengths while absorbing others. If one has paint with particles that only reflect green, adding particles that reflect red will allow some red light which would have been absorbed by a green particle... | |
| Feb 17, 2014 at 15:23 | vote | accept | Hal | ||
| Feb 16, 2014 at 23:20 | history | answered | hdhondt | CC BY-SA 3.0 |
