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Hello this may not be the answer you are seeking but i cannot comment and i would like to try helping you with the question so...

The main reason we use the car batteries that we use is efficiency that means that if we use a battery(household 12V) for a car it may start the engine once or twice but then the batteries die you see that a 12V battery on a 2 om (light) in a circuit will give you 6 A(ignoringI just researched more into the wire resistance) no matter what you usesubject and taking a closer look at A itfound out about what is called Voltage Drop which means when the amount of charge (electrons) passing through a wire in a second and so a 12V household battery can start a car's engine butamperes go up high the question is how many times? and that changes your questionvoltage starts to how much energy does a battery have?drop and here i stop since i know less about chemistry than i need to answer the question but i will do some research and then if i come up with an full answer i will edit this meanwhile this would be able to help people understand your question in a better way :) hope I helped.

After some research and looking into the matter a normal house hold 1.5V battery with a capacity of 3.4 Ah we get then put that into E=V.i.t (to get how much energy we will get)

E=1.53.43600(seconds in an hour) E=18360=0.018 MJ ofc we need 8 so 0.018*8=0.5 MJ

compared to a car-battery 12 V, 90 A·h

E=Vit E=(12 V)[ (90 A•Hr)(3600 sec/Hr) ] E=(3.888 ×10^6)J=(3.888) MJ

should i say more than that?

anyway i will continue that a car wouldcars need anywhere between 300 to 18000 watt-seconds (joules) to start but 300 is for a warm 4 cylinder that starts in one second which is pretty much isn't the most popular case and taking into consideration that the battery has more uses than just starting a car so your house batteries wouldn't be last as much timehigh as needed even with the dynamo feeding into it!

But if someone can help me with this and do the amount needed to keep the engine up300 and the energy from the dynamo (because400 in cold weather i have no knowledge about these) we will findam now working on numbers for that the batteries die after some time and i predict it will be basically few days as apposed to the months and sometimes years thatupdate when i figure the car batteries last formiss up!

Hello this may not be the answer you are seeking but i cannot comment and i would like to try helping you with the question so...

The main reason we use the car batteries that we use is efficiency that means that if we use a battery(household 12V) for a car it may start the engine once or twice but then the batteries die you see that a 12V battery on a 2 om (light) in a circuit will give you 6 A(ignoring the wire resistance) no matter what you use and taking a closer look at A it is the amount of charge (electrons) passing through a wire in a second and so a 12V household battery can start a car's engine but the question is how many times? and that changes your question to how much energy does a battery have? and here i stop since i know less about chemistry than i need to answer the question but i will do some research and then if i come up with an full answer i will edit this meanwhile this would be able to help people understand your question in a better way :) hope I helped.

After some research and looking into the matter a normal house hold 1.5V battery with a capacity of 3.4 Ah we get then put that into E=V.i.t (to get how much energy we will get)

E=1.53.43600(seconds in an hour) E=18360=0.018 MJ ofc we need 8 so 0.018*8=0.5 MJ

compared to a car-battery 12 V, 90 A·h

E=Vit E=(12 V)[ (90 A•Hr)(3600 sec/Hr) ] E=(3.888 ×10^6)J=(3.888) MJ

should i say more than that?

anyway i will continue that a car would need anywhere between 300 to 18000 watt-seconds (joules) to start but 300 is for a warm 4 cylinder that starts in one second which is pretty much isn't the most popular case and taking into consideration that the battery has more uses than just starting a car so your house batteries wouldn't be last as much time as needed even with the dynamo feeding into it!

But if someone can help me with this and do the amount needed to keep the engine up and the energy from the dynamo (because i have no knowledge about these) we will find that the batteries die after some time and i predict it will be basically few days as apposed to the months and sometimes years that the car batteries last for!

Hello this may not be the answer you are seeking but i cannot comment and i would like to try helping you with the question so...

I just researched more into the subject and found out about what is called Voltage Drop which means when the amperes go up high the voltage starts to drop and some cars need as high as 300 and 400 in cold weather i am now working on numbers for that will update when i figure the miss up!

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Hello this may not be the answer you are seeking but i cannot comment and i would like to try helping you with the question so...

The main reason we use the car batteries that we use is efficiency that means that if we use a battery(household 12V) for a car it may start the engine once or twice but then the batteries die you see that a 12V battery on a 2 om (light) in a circuit will give you 6 A(ignoring the wire resistance) no matter what you use and taking a closer look at A it is the amount of charge (electrons) passing through a wire in a second and so a 12V household battery can start a car's engine but the question is how many times? and that changes your question to how much energy does a battery have? and here i stop since i know less about chemistry than i need to answer the question but i will do some research and then if i come up with an full answer i will edit this meanwhile this would be able to help people understand your question in a better way :) hope I helped.

After some research and looking into the matter a normal house hold 1.5V battery with a capacity of 3.4 Ah we get then put that into E=V.i.t (to get how much energy we will get)

E=1.53.43600(seconds in an hour) E=18360=0.018 MJ ofc we need 8 so 0.018*8=0.5 MJ

compared to a car-battery 12 V, 90 A·h

E=Vit E=(12 V)[ (90 A•Hr)(3600 sec/Hr) ] E=(3.888 ×10^6)J=(3.888) MJ

should i say more than that?

anyway i will continue that a car would need anywhere between 300 to 18000 watt-seconds (joules) to start but 300 is for a warm 4 cylinder that starts in one second which is pretty much isn't the most popular case and taking into consideration that the battery has more uses than just starting a car so your house batteries wouldn't be last as much time as needed even with the dynamo feeding into it!

But if someone can help me with this and do the amount needed to keep the engine up and the energy from the dynamo (because i have no knowledge about these) we will find that the batteries die after some time and i predict it will be basically few days as apposed to the months and sometimes years that the car batteries last for!

Hello this may not be the answer you are seeking but i cannot comment and i would like to try helping you with the question so...

The main reason we use the car batteries that we use is efficiency that means that if we use a battery(household 12V) for a car it may start the engine once or twice but then the batteries die you see that a 12V battery on a 2 om (light) in a circuit will give you 6 A(ignoring the wire resistance) no matter what you use and taking a closer look at A it is the amount of charge (electrons) passing through a wire in a second and so a 12V household battery can start a car's engine but the question is how many times? and that changes your question to how much energy does a battery have? and here i stop since i know less about chemistry than i need to answer the question but i will do some research and then if i come up with an full answer i will edit this meanwhile this would be able to help people understand your question in a better way :) hope I helped.

After some research and looking into the matter a normal house hold 1.5V battery with a capacity of 3.4 Ah we get then put that into E=V.i.t (to get how much energy we will get)

E=1.53.43600(seconds in an hour) E=18360=0.018 MJ ofc we need 8 so 0.018*8=0.5 MJ

compared to a car-battery 12 V, 90 A·h

E=Vit E=(12 V)[ (90 A•Hr)(3600 sec/Hr) ] E=(3.888 ×10^6)J=(3.888) MJ

should i say more than that?

anyway i will continue that a car would need anywhere between 300 to 18000 watt-seconds (joules) to start but 300 is for a warm 4 cylinder that starts in one second which is pretty much isn't the most popular case and taking into consideration that the battery has more uses than just starting a car so your house batteries wouldn't be last as much time as needed even with the dynamo feeding into it!

Hello this may not be the answer you are seeking but i cannot comment and i would like to try helping you with the question so...

The main reason we use the car batteries that we use is efficiency that means that if we use a battery(household 12V) for a car it may start the engine once or twice but then the batteries die you see that a 12V battery on a 2 om (light) in a circuit will give you 6 A(ignoring the wire resistance) no matter what you use and taking a closer look at A it is the amount of charge (electrons) passing through a wire in a second and so a 12V household battery can start a car's engine but the question is how many times? and that changes your question to how much energy does a battery have? and here i stop since i know less about chemistry than i need to answer the question but i will do some research and then if i come up with an full answer i will edit this meanwhile this would be able to help people understand your question in a better way :) hope I helped.

After some research and looking into the matter a normal house hold 1.5V battery with a capacity of 3.4 Ah we get then put that into E=V.i.t (to get how much energy we will get)

E=1.53.43600(seconds in an hour) E=18360=0.018 MJ ofc we need 8 so 0.018*8=0.5 MJ

compared to a car-battery 12 V, 90 A·h

E=Vit E=(12 V)[ (90 A•Hr)(3600 sec/Hr) ] E=(3.888 ×10^6)J=(3.888) MJ

should i say more than that?

anyway i will continue that a car would need anywhere between 300 to 18000 watt-seconds (joules) to start but 300 is for a warm 4 cylinder that starts in one second which is pretty much isn't the most popular case and taking into consideration that the battery has more uses than just starting a car so your house batteries wouldn't be last as much time as needed even with the dynamo feeding into it!

But if someone can help me with this and do the amount needed to keep the engine up and the energy from the dynamo (because i have no knowledge about these) we will find that the batteries die after some time and i predict it will be basically few days as apposed to the months and sometimes years that the car batteries last for!

added 833 characters in body
Source Link

Hello this may not be the answer you are seeking but i cannot comment and i would like to try helping you with the question so...

The main reason we use the car batteries that we use is efficiency that means that if we use a battery(household 12V) for a car it may start the engine once or twice but then the batteries die you see that a 12V battery on a 2 om (light) in a circuit will give you 6 A(ignoring the wire resistance) no matter what you use and taking a closer look at A it is the amount of charge (electrons) passing through a wire in a second and so a 12V household battery can start a car's engine but the question is how many times? and that changes your question to how much energy does a battery have? and here i stop since i know less about chemistry than i need to answer the question but i will do some research and then if i come up with an full answer i will edit this meanwhile this would be able to help people understand your question in a better way :) hope I helped.

After some research and looking into the matter a normal house hold 1.5V battery with a capacity of 3.4 Ah we get then put that into E=V.i.t (to get how much energy we will get)

E=1.53.43600(seconds in an hour) E=18360=0.018 MJ ofc we need 8 so 0.018*8=0.5 MJ

compared to a car-battery 12 V, 90 A·h

E=Vit E=(12 V)[ (90 A•Hr)(3600 sec/Hr) ] E=(3.888 ×10^6)J=(3.888) MJ

should i say more than that?

anyway i will continue that a car would need anywhere between 300 to 18000 watt-seconds (joules) to start but 300 is for a warm 4 cylinder that starts in one second which is pretty much isn't the most popular case and taking into consideration that the battery has more uses than just starting a car so your house batteries wouldn't be last as much time as needed even with the dynamo feeding into it!

Hello this may not be the answer you are seeking but i cannot comment and i would like to try helping you with the question so...

The main reason we use the car batteries that we use is efficiency that means that if we use a battery(household 12V) for a car it may start the engine once or twice but then the batteries die you see that a 12V battery on a 2 om (light) in a circuit will give you 6 A(ignoring the wire resistance) no matter what you use and taking a closer look at A it is the amount of charge (electrons) passing through a wire in a second and so a 12V household battery can start a car's engine but the question is how many times? and that changes your question to how much energy does a battery have? and here i stop since i know less about chemistry than i need to answer the question but i will do some research and then if i come up with an full answer i will edit this meanwhile this would be able to help people understand your question in a better way :) hope I helped.

Hello this may not be the answer you are seeking but i cannot comment and i would like to try helping you with the question so...

The main reason we use the car batteries that we use is efficiency that means that if we use a battery(household 12V) for a car it may start the engine once or twice but then the batteries die you see that a 12V battery on a 2 om (light) in a circuit will give you 6 A(ignoring the wire resistance) no matter what you use and taking a closer look at A it is the amount of charge (electrons) passing through a wire in a second and so a 12V household battery can start a car's engine but the question is how many times? and that changes your question to how much energy does a battery have? and here i stop since i know less about chemistry than i need to answer the question but i will do some research and then if i come up with an full answer i will edit this meanwhile this would be able to help people understand your question in a better way :) hope I helped.

After some research and looking into the matter a normal house hold 1.5V battery with a capacity of 3.4 Ah we get then put that into E=V.i.t (to get how much energy we will get)

E=1.53.43600(seconds in an hour) E=18360=0.018 MJ ofc we need 8 so 0.018*8=0.5 MJ

compared to a car-battery 12 V, 90 A·h

E=Vit E=(12 V)[ (90 A•Hr)(3600 sec/Hr) ] E=(3.888 ×10^6)J=(3.888) MJ

should i say more than that?

anyway i will continue that a car would need anywhere between 300 to 18000 watt-seconds (joules) to start but 300 is for a warm 4 cylinder that starts in one second which is pretty much isn't the most popular case and taking into consideration that the battery has more uses than just starting a car so your house batteries wouldn't be last as much time as needed even with the dynamo feeding into it!

Source Link
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