Timeline for Would the Moon move away if the Earth were frozen with no liquid tide?
Current License: CC BY-SA 4.0
12 events
| when toggle format | what | by | license | comment | |
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| Jun 20 at 20:30 | history | became hot network question | |||
| Jun 20 at 15:56 | answer | added | BowlOfRed | timeline score: 3 | |
| Jun 20 at 15:10 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
tried to make title better
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| Jun 20 at 15:07 | comment | added | Francis Cagney | Thanks for your answer. So it's clear, freezing the Earth won't preserve full eclipses for our descendants. I will have to think of a different cunning plan. How about reversing the Earth's spin? That would be harmless wouldn't it? | |
| Jun 20 at 14:57 | comment | added | Confuse-ray30 | Two additions: The first is to clarify my first statement: If you hold something up (i.e. you is not necessarily you as a person) you exert force on an object without doing any work. The second concerns the "no work: statement: You do increase some energy, imagine the ice as being springs on molecules. Then the slight stretching of ice is work, given by (a toy model) $1/2 kx^2$. Where $k$ is some spring constant, x the displacement. | |
| Jun 20 at 14:53 | comment | added | Confuse-ray30 | Work cannot be done without force, force can act without work. Also, the force acting on stuff really only depends on distance and mass, so since frozen water is as "heavy" as liquid and neglecting the slight increase in height, the force is the same. Even including friction and whatnot. | |
| Jun 20 at 14:51 | comment | added | Francis Cagney | Well my argument (confusion?) is that the tides do work. Friction on the ocean floor, tidal power generation etc. Work is done when a force moves through a distance. No work, no force. If the Earth were solid the moon's gravity would do no work. | |
| Jun 20 at 14:45 | comment | added | Confuse-ray30 | Then your argument is flawed since gravitational pull is independent of what it pulls on. So even if the tidal effect (in amplitude) on mountains and other solid matter is smaller, the force acting on the moon is the same. (Barring some effects from the fact matter moves a tiny bit nearer). So no, it shouldnt change of any significance | |
| Jun 20 at 14:34 | comment | added | Francis Cagney | The tides are caused by the moon's gravity pulling on the sea causing it to bulge slightly at the part of the Earth facing the moon* As the Earth rotates this bulge moves over the surface of the Earth. Equal and opposite, if the mopon pulls this bulge, then this bulge pulls the moon. That's waht I mean by a tidal leash * Gross simplification. To be technical there is a bulge facing the moon as a result of stronger lunar gravity, and away from the moon as a result of string centrifugal force, but this is not relevant to the question | |
| Jun 20 at 13:35 | comment | added | Confuse-ray30 | Whats a tidal leash? The same thing as a tide? | |
| S Jun 20 at 12:28 | review | First questions | |||
| Jun 20 at 12:33 | |||||
| S Jun 20 at 12:28 | history | asked | Francis Cagney | CC BY-SA 4.0 |