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Physics

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  • $\begingroup$ If you only have two events, you do not have enough information to distinguish between all the possible cases. Nowhere in your question have you given us any expectation for the acceleration to be any specific value. Why did you think you would get agreement? $\endgroup$
    – naturallyInconsistent
    Commented May 22 at 12:24
  • 1
    $\begingroup$ You are using $t$ to mean two different things. In the line $v = s/t = ...$ you are using $t$ to mean the time interval from start to finish of the motion, i.e. the value of time at the end minus the value of time at the start. When you then do $ds/dt$, you are using $t$ to mean the time value at the end of the motion. You should use something like $v = \Delta s / \Delta t = ...$ for the former case. $\endgroup$
    – Marius Ladegård Meyer
    Commented May 22 at 14:01