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    $\begingroup$ As Andrew’s answer says, “the equation of motion for (say) $\vec{q}^1$ at time $t$ depends on the positions of all the other particles $\vec{q}^2, \cdots \vec{q}^N$ at time $t$”. This is “true instantaneous action at a distance” as far as I’m concerned. $\endgroup$
    – Ghoster
    Commented May 7 at 6:44
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    $\begingroup$ @Cory As explained on "de Broglie–Bohm" Wikipedia, a relativistic version also exists (by just straightforwardly applying it to relativistic quantum field theory, see: arxiv.org/abs/quant-ph/0202104 and arxiv.org/abs/quant-ph/0407089 ). But even if you restrict yourself to the nonrelativistic case there is still nothing else going on then in nonrelativistic schroedinger wavefunctions! So please explain, what has BM got to do with it? $\endgroup$
    – Jos Bergervoet
    Commented May 7 at 6:44
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    $\begingroup$ Just curious: Are you a physics student or a philosophy student? (Anyone interested in physics is welcome here, regardless of what they are studying.) I see that you prefer the Stanford Encyclopedia of Philosophy to physics articles in Wikipedia. $\endgroup$
    – Ghoster
    Commented May 7 at 6:48
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    $\begingroup$ @Ghoster I am neither, I’m a software engineer and I’m interested in physics, philosophy and math. Also, those SEP articles are arguably more reliable than Wikipedia, are they not? Of course both can be useful. Just to also add, that particular article is written by a physicist. $\endgroup$
    – user401242
    Commented May 7 at 7:34
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    $\begingroup$ I'm a theoretical physicist and also worked in engineering, therefore I do not know what you mean with "seemingly instantaneous action", also not if you replace that with "influence". I only see a differential equation for $\psi$, and that describes everything. The words you use have no meaning if you can't relate them to the equations that comprise the theory. $\endgroup$
    – Jos Bergervoet
    Commented May 7 at 7:40