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Post Reopened by Connor Behan, John Rennie, gandalf61
I made it more apparent that this question is more about understanding the concepts needed to set up the problem. I have no desire to gain any help solving the actual problem.
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The system I am considering consists of a conducting liquid sandwiched between two electrodes.

The electrodes supply a constant flux of electrons $j_{ext}$$J_{ext}$.

In the liquid there are also uncharged particles, call them $A$, that can capture the electrons and gain charge, lets call them $A^-$.

I am looking for the steady state concentration profile of both $A$ and $A^-$.

From the continuity equation for steady state

$$\nabla \cdot j=0$$

where we get the following set of differential equations in 1D

$$\frac{dJ_A}{dx}=-k C_A C_e$$

$$\frac{dJ_{A^-}}{dx}=k C_A C_e$$

$$\frac{dJ_{e}}{dx}=-k C_A C_e$$

where J's are the fluxes and C's the concentrations for the non-charged particles, charged particles and electrons. k is the rate constant for conversion between electrons and the charged particles.

From charge conservation it then follows that $J_{A^-}+J_e=J_{ext}$ so we can remove one of the differential equations by enforcing this constraint.

At the bottom electrode we have no flux of the charged and uncharged species, i.e $J_{A^-}=J_A=0$.

At the top we have the generation of uncharged particles as the charged ones lose their electrons to the electrode. Namely $J_{A^-}=-J_A$.

Thus we have two differential equations of second order (as $j\propto \nabla C$) and 3 boundary conditions, so I am missing one. The current BCs already conserve electric charge and particle number.

Can anyone spot whatWhat other possible constraints are there on this system that would lead to a well-defined problem?

**Edit: I am missing?asking for the physical concepts, e.g some conserved quantity, that gives me the correct boundary conditions that would allow me to turn this into a well posed differential equation problem. **

The system I am considering consists of a conducting liquid sandwiched between two electrodes.

The electrodes supply a constant flux of electrons $j_{ext}$.

In the liquid there are also uncharged particles, call them $A$, that can capture the electrons and gain charge, lets call them $A^-$.

I am looking for the steady state concentration profile of both $A$ and $A^-$.

From the continuity equation for steady state

$$\nabla \cdot j=0$$

where we get the following set of differential equations in 1D

$$\frac{dJ_A}{dx}=-k C_A C_e$$

$$\frac{dJ_{A^-}}{dx}=k C_A C_e$$

$$\frac{dJ_{e}}{dx}=-k C_A C_e$$

where J's are the fluxes and C's the concentrations for the non-charged particles, charged particles and electrons. k is the rate constant for conversion between electrons and the charged particles.

From charge conservation it then follows that $J_{A^-}+J_e=J_{ext}$ so we can remove one of the differential equations by enforcing this constraint.

At the bottom electrode we have no flux of the charged and uncharged species, i.e $J_{A^-}=J_A=0$.

At the top we have the generation of uncharged particles as the charged ones lose their electrons to the electrode. Namely $J_{A^-}=-J_A$.

Thus we have two differential equations of second order (as $j\propto \nabla C$) and 3 boundary conditions, so I am missing one. The current BCs already conserve electric charge and particle number.

Can anyone spot what I am missing?

The system I am considering consists of a conducting liquid sandwiched between two electrodes.

The electrodes supply a constant flux of electrons $J_{ext}$.

In the liquid there are also uncharged particles, call them $A$, that can capture the electrons and gain charge, lets call them $A^-$.

I am looking for the steady state concentration profile of both $A$ and $A^-$.

From the continuity equation for steady state

$$\nabla \cdot j=0$$

where we get the following set of differential equations in 1D

$$\frac{dJ_A}{dx}=-k C_A C_e$$

$$\frac{dJ_{A^-}}{dx}=k C_A C_e$$

$$\frac{dJ_{e}}{dx}=-k C_A C_e$$

where J's are the fluxes and C's the concentrations for the non-charged particles, charged particles and electrons. k is the rate constant for conversion between electrons and the charged particles.

From charge conservation it then follows that $J_{A^-}+J_e=J_{ext}$ so we can remove one of the differential equations by enforcing this constraint.

At the bottom electrode we have no flux of the charged and uncharged species, i.e $J_{A^-}=J_A=0$.

At the top we have the generation of uncharged particles as the charged ones lose their electrons to the electrode. Namely $J_{A^-}=-J_A$.

Thus we have two differential equations of second order (as $j\propto \nabla C$) and 3 boundary conditions, so I am missing one. The current BCs already conserve electric charge and particle number.

What other possible constraints are there on this system that would lead to a well-defined problem?

**Edit: I am asking for the physical concepts, e.g some conserved quantity, that gives me the correct boundary conditions that would allow me to turn this into a well posed differential equation problem. **

Post Closed as "Not suitable for this site" by BioPhysicist, Jon Custer, Vincent Thacker
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Need help identifying missing boundary condition in charge transport problem

The system I am considering consists of a conducting liquid sandwiched between two electrodes.

The electrodes supply a constant flux of electrons $j_{ext}$.

In the liquid there are also uncharged particles, call them $A$, that can capture the electrons and gain charge, lets call them $A^-$.

I am looking for the steady state concentration profile of both $A$ and $A^-$.

From the continuity equation for steady state

$$\nabla \cdot j=0$$

where we get the following set of differential equations in 1D

$$\frac{dJ_A}{dx}=-k C_A C_e$$

$$\frac{dJ_{A^-}}{dx}=k C_A C_e$$

$$\frac{dJ_{e}}{dx}=-k C_A C_e$$

where J's are the fluxes and C's the concentrations for the non-charged particles, charged particles and electrons. k is the rate constant for conversion between electrons and the charged particles.

From charge conservation it then follows that $J_{A^-}+J_e=J_{ext}$ so we can remove one of the differential equations by enforcing this constraint.

At the bottom electrode we have no flux of the charged and uncharged species, i.e $J_{A^-}=J_A=0$.

At the top we have the generation of uncharged particles as the charged ones lose their electrons to the electrode. Namely $J_{A^-}=-J_A$.

Thus we have two differential equations of second order (as $j\propto \nabla C$) and 3 boundary conditions, so I am missing one. The current BCs already conserve electric charge and particle number.

Can anyone spot what I am missing?