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Mar 4 at 3:08 comment added ShKol You already have $A_{\mu} = \epsilon_{\mu}(p)e^{ipx}$. Choose $\alpha = -if(p)e^{ipx}$. This means the gauge transformed field is $A_{\mu} = \epsilon_{\mu}(p)e^{ipx} + \partial_{\mu}(-if(p)e^{ipx}) = ( \epsilon_{\mu}(p) +f(p)p_{\mu})e^{ipx}$ which is the new solution that has been proposed.
Mar 3 at 16:54 comment added Sophie Schot I'm sorry, I don't think I'm quite understanding, do you mean that $\alpha = f(p)p_{\mu}$ generates the proposed ansatz?
S Mar 3 at 16:01 history suggested ShKol CC BY-SA 4.0
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Mar 3 at 15:13 comment added ShKol I think you need to show that $\alpha = f(p)e^{ipx}$ generates the proposed ansatz (which you have verified is also a solution to the vacuum equation).
Mar 3 at 15:03 review Suggested edits
S Mar 3 at 16:01
Mar 3 at 14:26 history edited Qmechanic CC BY-SA 4.0
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Mar 3 at 13:29 history edited Sophie Schot CC BY-SA 4.0
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S Mar 3 at 13:29 review First questions
Mar 3 at 14:27
S Mar 3 at 13:29 history asked Sophie Schot CC BY-SA 4.0