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Nov 23, 2023 at 2:19 comment added Jacob Ivanov @Eli, how so? Wouldn't it be: $$dW = c \frac{dx}{dt} dt$$ Either way, how would that change anything?
Nov 22, 2023 at 16:37 comment added Eli Write it like this $~ dW=c\,\dfrac{dx}{dt}\,\dfrac{dx}{dt}\,dt$
Nov 22, 2023 at 2:46 history edited Qmechanic
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Nov 21, 2023 at 22:39 comment added Lourenco Entrudo The "dividing by dt" step is entirely legitimate, because it is not dividing by dt. Let me refer you to this related answer I gave someone a while back which might be helpful in putting you at ease here
S Nov 21, 2023 at 22:30 review First questions
Nov 21, 2023 at 22:46
S Nov 21, 2023 at 22:30 history asked Jacob Ivanov CC BY-SA 4.0