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Physics

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  • $\begingroup$ To avoid 0/0 take the limit so your values approach, but are not really 0. $\endgroup$
    – Yukterez
    Commented May 12, 2023 at 23:03
  • $\begingroup$ No, for a = const and v = 0 that really means that $\frac{\mathrm dv}{\mathrm dx}\to\infty$ $\endgroup$
    – naturallyInconsistent
    Commented May 13, 2023 at 3:16