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Post Reopened by hyportnex, Michael Seifert, GiorgioP-DoomsdayClockIsAt-90
Post Closed as "Duplicate" by Roger V., Bob D thermodynamics
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Thomas Fritsch
Thomas Fritsch
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We can only speak of entropy change, dS$dS$, when I mention Clausius as dS=δQ/T$$dS=δQ/T$$

However, according to Boltzmann, entropy is defined as S=KlnΩ$S=K\ln\Omega$

My question is, is the 'S'$S$ according to Boltzmann an entropy change as well? Or is it the entropy of the satestate whose disorder number is Ω$\Omega$ and accordingly, ds=kln(Ω_2/Ω_1)$ds=k\ln(\Omega_2/\Omega_1)$?

We can only speak of entropy change, dS, when I mention Clausius as dS=δQ/T

However, according to Boltzmann, entropy is defined as S=KlnΩ

My question is, is the 'S' according to Boltzmann an entropy change as well? Or is it the entropy of the sate whose disorder number is Ω and accordingly, ds=kln(Ω_2/Ω_1)?

We can only speak of entropy change, $dS$, when I mention Clausius as $$dS=δQ/T$$

However, according to Boltzmann, entropy is defined as $S=K\ln\Omega$

My question is, is the $S$ according to Boltzmann an entropy change as well? Or is it the entropy of the state whose disorder number is $\Omega$ and accordingly, $ds=k\ln(\Omega_2/\Omega_1)$?

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Qmechanic ♦
Qmechanic ♦
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Jack
Jack
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What is the difference between Clausius' entropy and Boltzmann's?

We can only speak of entropy change, dS, when I mention Clausius as dS=δQ/T

However, according to Boltzmann, entropy is defined as S=KlnΩ

My question is, is the 'S' according to Boltzmann an entropy change as well? Or is it the entropy of the sate whose disorder number is Ω and accordingly, ds=kln(Ω_2/Ω_1)?