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mmesser314
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Adding to Dale's answer, the dimensions of a dime are $7.91$$17.91$ mm diameter and $1.35$ mm thick. So the volume is $66.34$$341.1$ mm$^3$.

If you spread that out over a football field with an area of $7200 \cdot 10^6$ mm$^2$, the thickness is $9.21 \cdot 10^{-9}$$4.72 \cdot 10^{-8}$ mm. Or about $1/10^{th}$ of$1/2$ an atom thick.

Adding to Dale's answer, the dimensions of a dime are $7.91$ mm diameter and $1.35$ mm thick. So the volume is $66.34$ mm$^3$.

If you spread that out over a football field with an area of $7200 \cdot 10^6$ mm$^2$, the thickness is $9.21 \cdot 10^{-9}$ mm. Or about $1/10^{th}$ of an atom thick.

Adding to Dale's answer, the dimensions of a dime are $17.91$ mm diameter and $1.35$ mm thick. So the volume is $341.1$ mm$^3$.

If you spread that out over a football field with an area of $7200 \cdot 10^6$ mm$^2$, the thickness is $4.72 \cdot 10^{-8}$ mm. Or about $1/2$ an atom thick.

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mmesser314
  • 41.1k
  • 5
  • 53
  • 136

Adding to Dale's answer, the dimensions of a dime are $7.91$ mm diameter and $1.35$ mm thick. So the volume is $66.34$ mm$^3$.

If you spread that out over a football field with an area of $7200 \cdot 10^6$ mm$^2$, the thickness is $9.21 \cdot 10^{-9}$ mm. Or about $1/10^{th}$ of an atom thick.