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    $\begingroup$ This is a much more useful answer than the other! Might be worth adding that this is (kind of) because electrons are not quarks, nor are they made up of quarks, while protons and neutrons are composed of quarks. $\endgroup$
    – Carl Witthoft
    Commented Sep 20, 2021 at 14:53
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    $\begingroup$ @CarlWitthoft I do not agree, it is a reasoning of why the nuclei have a large mass while electrons cannot attain such densities , but it has nothing to do with explaining why the heavy mass of the nucleus defines a tight orbital for it in the atomic center of mass. The Bohr model gives an envelope of how the full quantum mechanical calculation would give the orbitals. Take the hydrogen atom: in the center of mass system from adding the two momenta to zero, the heavy proton will have a much smaller velocity than the light electron, making a much smaller circle. Similar to $\endgroup$
    – anna v
    Commented Sep 20, 2021 at 17:49
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    $\begingroup$ This seems to answer an older version of the question before an edit was made $\endgroup$
    – Paul T.
    Commented Sep 20, 2021 at 18:09
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    $\begingroup$ Given the OP's acceptance of the other answer, I would assume they were really asking the edited version even if they did not articulate it at first. $\endgroup$
    – Paul T.
    Commented Sep 20, 2021 at 19:27
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    $\begingroup$ The point made by this answer is important in general, but for a neutral ${}^1\text{H}$ atom there is only one proton and one electron, so the strong force does not come into play. (Not at the atomic scale, anyway. One could talk about the mass of the proton being ~90% from the dynamics of its quarks, which is largely governed by the strong force, but that takes us back into the territory of the other answer IMO.) $\endgroup$
    – zwol
    Commented Sep 21, 2021 at 14:02