Timeline for Why should water fall down from an upside down glass of water?
Current License: CC BY-SA 4.0
20 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 29, 2021 at 12:47 | answer | added | Deschele Schilder | timeline score: 1 | |
| May 29, 2021 at 6:42 | vote | accept | FullBridge | ||
| May 29, 2021 at 0:00 | history | tweeted | twitter.com/StackPhysics/status/1398428906017935362 | ||
| May 28, 2021 at 15:41 | comment | added | QCD_IS_GOOD | physics.stackexchange.com/questions/140941/… similar question - as the answers point out the configuration is not really stable, and suffers Rayleigh-Taylor instability | |
| May 28, 2021 at 13:56 | history | became hot network question | |||
| May 28, 2021 at 13:22 | history | edited | Dale | CC BY-SA 4.0 |
added 4 characters in body
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| May 28, 2021 at 13:18 | answer | added | Dale | timeline score: 59 | |
| May 28, 2021 at 11:01 | answer | added | Sidarth | timeline score: 0 | |
| May 28, 2021 at 10:53 | comment | added | Sidarth | I have to agree that pressure from the air is only on one side of the water. I started thinking of your water as solid ice, making it better to think about. In case the glass was a cylinder then as the ice block block falls, the vaccum suction in the top will prevent the ice from falling down. That is certainly true. | |
| May 28, 2021 at 10:46 | comment | added | FullBridge | @Sidarth The water won't exert its weight but the excess pressure from the atmosphere could cause $F_g$ to be non zero right? | |
| May 28, 2021 at 10:44 | comment | added | Sidarth | Sorry this stupid phone keeps doing wrong things. I hit enter without intending to. | |
| May 28, 2021 at 10:41 | comment | added | Sidarth | In your question ,F_g is the force from the glass. It is a reactionary force. There will be a non zero f_g only when the water is exerting it's weight on the glass' walls. Otherwise why /how will the glass exert a force on the water? | |
| May 28, 2021 at 10:40 | comment | added | FullBridge | @Sidarth Why would there not be any $F_g$ if I hold it? | |
| May 28, 2021 at 10:24 | comment | added | Sidarth | Is the glass allowed to free with the water or will you hold it? In case you hold it, there won't be any F_g | |
| May 28, 2021 at 6:08 | comment | added | FullBridge | @DKNguyen Yes that or the angle of slope can be considered very small. | |
| May 28, 2021 at 5:57 | answer | added | PcMan | timeline score: 1 | |
| May 28, 2021 at 5:47 | answer | added | Bill Watts | timeline score: 0 | |
| May 28, 2021 at 5:21 | answer | added | lamplamp | timeline score: 7 | |
| May 28, 2021 at 5:19 | comment | added | DKNguyen | Did you mean for your cup to be cylindrical and not tapered? Because reducing V would decrease A. | |
| May 28, 2021 at 4:42 | history | asked | FullBridge | CC BY-SA 4.0 |