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Sep 27, 2022 at 21:18 vote accept Tanatofobico
Feb 15, 2020 at 11:32 comment added Tanatofobico @Aaron If it it seen as an equation for the VEV, it allows the VEV to take a non-zero value. I feel like my mistake is confusing a possible VEV solution with the VEV as calculated in a non broken theory.
Feb 15, 2020 at 2:17 answer added Seth Whitsitt timeline score: 4
Feb 14, 2020 at 23:10 comment added SRS Related physics.stackexchange.com/questions/285990/… , physics.stackexchange.com/questions/257559/…
Feb 14, 2020 at 19:38 comment added Aaron For the second bullet, why do you think there is a contradiction? One is a statement about $\phi$ and the other about $\Gamma$ (namely, it's $\phi$ dependence).
Feb 14, 2020 at 17:16 history asked Tanatofobico CC BY-SA 4.0