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  • $\begingroup$ For the second bullet, why do you think there is a contradiction? One is a statement about $\phi$ and the other about $\Gamma$ (namely, it's $\phi$ dependence). $\endgroup$
    – Aaron
    Commented Feb 14, 2020 at 19:38
  • $\begingroup$ Related physics.stackexchange.com/questions/285990/… , physics.stackexchange.com/questions/257559/… $\endgroup$
    – SRS
    Commented Feb 14, 2020 at 23:10
  • $\begingroup$ @Aaron If it it seen as an equation for the VEV, it allows the VEV to take a non-zero value. I feel like my mistake is confusing a possible VEV solution with the VEV as calculated in a non broken theory. $\endgroup$
    – Tanatofobico
    Commented Feb 15, 2020 at 11:32