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Jun 25, 2023 at 13:16 comment added tparker I think it's worth clarifying that frictional forces reduce relative motion between two surfaces in contact. If you slowly pull a tablecloth out from a loaded table, then the friction between the cloth and the plates will cause the plates to speed up (in your frame of reference), not slow down. The fact that the direction of frictional forces depends on relative rather than absolute motion follows from the Galilean invariance of Newtonian physics, but it may not be obvious to a beginner.
Dec 10, 2018 at 14:48 comment added rebusB @user71659 - if your car was moving 0.0000000000000001 mph would you notice or would you consider it stopped?
Dec 10, 2018 at 11:53 comment added Peter - Reinstate Monica @Draco18s There are different types of friction; dynamic dry friction (e.g. skidding wheel on street) does not depend on the speed, so it is purely additive (but vanishes when the car comes to a stop, which is why the car doesn't start going backwards).
Dec 9, 2018 at 22:55 comment added vol7ron “But they also slow down motion that produces reverse movement” I feel this comment is confusing (irrelevant) to the question. There is no negative force under review. Friction doesn’t cause negativity, it only reduces positivity; like hitting a puck on ice vs asphalt.
Dec 9, 2018 at 6:36 comment added corsiKa @DanStaley Zeno would agree with you.
Dec 9, 2018 at 4:32 comment added zahbaz @Krumia Funny, I pictured the spring attached to the rear of the car.
Dec 8, 2018 at 0:20 comment added user71659 @DanStaley You can't stop a car unless it's at absolute zero...
Dec 7, 2018 at 20:45 comment added JiK @Draco18s How does introducing "multiplicative" simplfy anything?
Dec 7, 2018 at 18:58 comment added Draco18s no longer trusts SE @JiK What part of "simplified analogy" wasn't clearly communicated?
Dec 7, 2018 at 18:46 comment added JiK @Draco18s In what way is friction multiplicative?
Dec 7, 2018 at 5:37 vote accept Harnoor Lal
Dec 6, 2018 at 20:26 comment added Draco18s no longer trusts SE @DanStaley Oh its definitely a simplification. :) (and you can multiply by 0.9 enough times to get to effectively 0, as the value is so small as to be meaningless over the timescales involved, but point taken).
Dec 6, 2018 at 19:54 comment added Dan Staley @Draco18s An interesting simplification, although if true it would mean you can't stop your car with the brakes (no amount of multiplying by 0.9 will ever make a positive number zero either)!
S Dec 5, 2018 at 22:52 history suggested CJ Dennis CC BY-SA 4.0
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Dec 5, 2018 at 22:24 review Suggested edits
S Dec 5, 2018 at 22:52
Dec 5, 2018 at 21:56 comment added Draco18s no longer trusts SE Essentially: braking (friction) is a multiplicative. No amount of multiplying by 0.9 will ever make a positive number negative. Rockets, on the other hand, are additive (and you can absolutely add a negative number to a positive one and end up with a negative number).
Dec 5, 2018 at 15:44 history edited Chemomechanics CC BY-SA 4.0
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Dec 5, 2018 at 15:43 comment added Bradley Uffner @OscarBravo SpaceX's high speed u-turn that the first stage booster's do when going back to the landing pad, is a great example of exactly what you are talking about.
Dec 5, 2018 at 15:25 comment added Oscar Bravo This is how a spacecraft slows down. It rotates so that its rocket nozzle is pointing in the direction of motion. Then it fires the rocket to produce a force and decelerate. If it kept the motor burning, it would eventually stop and then accelerate back the way it came.
Dec 5, 2018 at 12:54 comment added infinitezero Or just use a turbine that accelerates you backwards as breaking mechanism.
Dec 5, 2018 at 7:12 comment added sampathsris Thanks for the mental image of a car slamming into a giant spring.
Dec 5, 2018 at 5:37 comment added Nelson A better example would be crashing into a very solid barrier. The car will bounce backwards...
Dec 5, 2018 at 2:24 comment added Mazura Acceleration is "the rate of change of velocity per unit of time" . It is not a force-applying [mechanism]. +1
Dec 5, 2018 at 0:44 history answered Chemomechanics CC BY-SA 4.0