Timeline for Why do lines in atomic spectra have thickness? (Bohr's Model)
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Mar 29, 2015 at 17:48 | history | edited | bernd | CC BY-SA 3.0 |
link to wolfram alpha. the lines in the picture are too broad to match the result.
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| Mar 29, 2015 at 16:47 | history | edited | bernd | CC BY-SA 3.0 |
doppler broadening is not the only broadening; picture shows doppler broadening.
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| Mar 29, 2015 at 16:42 | comment | added | zeldredge | This is only part of the answer. Even using spectroscopy that eliminates the Doppler shift, there is an innate Lorentzian line spread. | |
| Mar 29, 2015 at 16:38 | comment | added | bernd | Actually the final acceptance is governed by the energy-time uncertainty m0nhawk mentioned in his answer. But normally (in 19th century physics) you do not observe single atoms. When you take $10^{23}$ atoms , their velocities are not the same but distributed (Maxwell&Boltzmann distribution). So you have a good chance that some of your atoms actually match the doppler shifted light frequency. Since they move in different directions with different velocities your observed spectral line is quite broad. | |
| Mar 29, 2015 at 16:31 | comment | added | Gerard | So, if I'm correct, what you're saying is that light of frequencies different from that of the transition frequency is doppler shifted to the transition frequency. However, the atom still must 'accept' a range of values, since there is a 0 probability that any frequency will be shifted to the exact transition frequency. | |
| Mar 29, 2015 at 16:26 | history | answered | bernd | CC BY-SA 3.0 |