Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with perfect-matchings
Search options not deleted
user 141766
A perfect matching is a matching of all the vertices of a graph. In other words, a perfect matching is a set of edges such that each vertex of the graph is incident to exactly one edge in the set.
1
vote
Disjoint perfect matchings in complete bipartite graph
For fixed $n$, you can solve the problem via integer linear programming as follows. For edge $(i,j)\in E$ and matching $k\in\{1,\dots,n-1\}$, let binary decision variable $x_{i,j,k}$ indicate whether …
- 5,219
0
votes
What is known about iterated matching as a TSP heuristic
For optimally merging pairs of paths, you can introduce a complete graph with one node per path and edge weight for each path pair $(i,j)$ equal to the minimum of the four possible original edge weigh …
- 5,219
7
votes
Accepted
Connecting $2n$ points in $\mathbb R^2$ with line segments s.t. each point belongs to exactl...
You can solve this as a minimum-weight perfect matching problem in a graph with a node for each point and an edge for each pair of points. Because the distances satisfy the triangle inequality, an op …
- 5,219