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4 votes
1 answer
486 views

Truth Values of Statements in non-standard models

Excuse me, if the question sounds too naive. Non-standard models of PA will have statements of non-standard lengths, basically infinite. And it is also true that every statement of a theory will have ...
Amiren's user avatar
  • 1
4 votes
0 answers
152 views

Can this theory of dyadic rationals prove that multiplying by three is the same as summing thrice?

(This question arose from a discussion with Jade Vanadium about a theory of dyadic rationals.) Let $T$ be the 2-sorted FOL theory with sorts $ℕ,ℚ$ and constant-symbols $0,1$ and binary function-...
user21820's user avatar
  • 2,848
1 vote
1 answer
216 views

Seeking clarification of ultrapower nonstandard model of arithmetic

I've read that one nonstandard model of arithmetic is: take $\mathbb{N}^\mathbb{N}$, the set of countably infinite sequences of natural numbers take a quotent that gives the ultrapower: identify ...
Dave Pritchard's user avatar
14 votes
1 answer
598 views

Extensions of $PA+\neg Con(PA)$ with large consistency strength

There is a large hierarchy of theories strengthening $PA$ eg $PA+Con(PA)$, $PA+Con(PA+Con(PA))$,..., second-order arithmetic and $ZFC$, ordered by consistency strength. Is there an extension of $PA+\...
Tom Bouley's user avatar
15 votes
5 answers
3k views

How is it possible for PA+¬Con(PA) to be consistent?

I'm having some trouble understanding how a certain first-order theory isn't just straight-up inconsistent. Let $PA$ be the axioms of (first-order) Peano arithmetic and let $C$ be the following ...
E8 Heterotic's user avatar
10 votes
2 answers
424 views

The additive structure of clusters of nonstandard models of arithmetic

Given $\frak M$ a countable nonstandard model of $\sf PA$ and let $a\in M$ be a nonstandard element. A "cluster around $a$" is the set of successors and predecessors of $a$, a cluster is a ...
Holo's user avatar
  • 1,654
7 votes
0 answers
108 views

How tightly are decidability and "induction-completeness" linked?

It is known that there are a number of expansions of the structure $\mathfrak{N}:=(\mathbb{N};+)$ which are decidable (= have computable theories); one such example is the expansion by a predicate ...
Noah Schweber's user avatar
11 votes
2 answers
370 views

Can singular long models require less than PA?

Say that a long model is an $\mathfrak{A}\models\mathsf{I\Sigma_1}$ such that $\mathfrak{A}$ has strictly greater cardinality than each of its proper initial segments (in the case $\vert\mathfrak{A}\...
Noah Schweber's user avatar
5 votes
1 answer
141 views

Does visible nonstandardness imply visible ill-foundedness?

For $X\subseteq\mathfrak{M}\models \mathsf{TA}$, say that $X$ is $\mathfrak{M}$-disruptive iff there is some formula $\varphi$ in the language of arithmetic + a new unary predicate symbol $U$ such ...
Noah Schweber's user avatar
7 votes
1 answer
237 views

What is known about first order logic of $\mathbb{N}$ with + and a unary predicate?

In "Weak Second-Order Arithmetic and Finite Automata", Büchi claims that the first order theory of $\mathbb{N}$ with + and a predicate for recognizing powers of 2 ($Pw_2$) is expressively ...
TomKern's user avatar
  • 429
6 votes
1 answer
270 views

A "negative" standard system

For $\mathcal{M}$ a (countable) nonstandard model of $\mathsf{PA}$, let $\mathsf{SS}(\mathcal{M})$ be the set of sets of natural numbers coded by elements of $\mathcal{M}$. There are various ways to ...
Noah Schweber's user avatar
0 votes
1 answer
235 views

Is there a non-standard model of PA computable with infinitary computation?

By the Tennenbaum's theorem, there are no non-standard countable models of Peano Arithmetic that are computable using Turing machines. What about models of infinitary computation like infinite time ...
Jozef Mikušinec's user avatar
4 votes
1 answer
420 views

Alternative proof of Tennenbaum's theorem

The standard proof of Tennenbaums's theorem uses the existence of recursively enumerable inseparable sets and is presented e.g. in Kaye [1, 2], Smith [3]. In the following, $\mathcal{M}$ will always ...
Léreau's user avatar
  • 211
7 votes
0 answers
283 views

Generic behavior of "polynomialish" models of $\mathsf{Q}$

(This question was originally asked and bountied at MSE - with different notation, some more explicit arguments, and topology in place of forcing.) Suppose $\mathcal{R}=(R_i)_{i\in\mathbb{N}}$ is a ...
Noah Schweber's user avatar
5 votes
0 answers
304 views

$\Sigma_n$-complete sets in the Levy hierarchy

Recall that a set $A \subseteq \mathbb N$ is (many-one, Turing) $\Sigma_n$-complete if it's $\Sigma_n$ and any other $\Sigma_n$ set (many-one, Turing) reduces to it. This definition actually makes ...
Corey Bacal Switzer's user avatar

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