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5 votes
1 answer
193 views

What is the theory of computably saturated models of ZFC with an *externally well-founded* predicate?

For any model of $M$ of ZFC, we can extend it to a model $M_{ew}$ with an "externally well-founded" predicate $ew$. For $x \in M$, We say that $M_{ew} \vDash ew(x)$ when there is no infinite ...
Christopher King's user avatar
6 votes
5 answers
2k views

Standard models of N and R: An Alice/Bob approach

This is a question about a comment in a recent publication by Roman Kossak. Kossak wrote: "Nonstandardness in set theory has a different nature. In arithmetic, there is one intended object of ...
Mikhail Katz's user avatar
  • 15.8k
9 votes
1 answer
288 views

Transfinitely iterating the Levi-Civita, Hahn or Puiseux constructions

This question was originally asked at MSE but seems too advanced, so I'm reposting it here. In short, the idea is that many constructions for non-Archimedean fields can naturally be iterated, in some ...
Mike Battaglia's user avatar
12 votes
2 answers
551 views

Decidability of a first-order theory of hyperreals

The theory of real closed fields is decidable. The hyperreals satisfy that theory, so we can interpret statements in the theory of real closed fields as being about hyperreals. If we add a unary ...
Christopher King's user avatar
6 votes
0 answers
196 views

Isomorphism of hyperreal fields viewed as extensions of the field of reals

I asked this question on Mathematics Stackexchange but got no answer. Question. Does $ZFC$ prove that there are non-principal ultrafilters $\mathcal U$ and $\mathcal V$ over $\mathbb N$ such that the ...
Pierre-Yves Gaillard's user avatar
9 votes
2 answers
442 views

Can nonstandard fields contain $\mathbb R$ in different ways?

Suppose $e : \mathbb R \to F$ is an elementary embedding in the language of ordered fields. Can there exist an elementary embedding $e' : \mathbb R \to F$ such that $e \not= e'$? Note that it would ...
Monroe Eskew's user avatar
  • 18.1k
6 votes
1 answer
321 views

Cofinality of infinitesimals

Suppose $\kappa$ is an infinite cardinal and $U$ is a countably incomplete uniform ultrafilter over $\kappa$. Then $\mathbb R^\kappa/U$ is nonstandard. What is the cofinality of the set of ...
Monroe Eskew's user avatar
  • 18.1k
2 votes
0 answers
170 views

How to construct "inaccessible hypernatural"?

Consider that, take a sufficient large natural number $a_1$, then take a natural number $a_2$ sufficient large to $a_1$, then take $a_3$,... Now we have a function $n \mapsto a_n$ which grows very ...
QiRenrui's user avatar
  • 475
4 votes
0 answers
144 views

Self homomorphisms of hyperreals fixing the reals

What do we know about the circumstances (whether having to do with the axioms of set theory or the model itself) under which a field $F$ of hyperreals (=ultrapower of $\mathbb R$ with respect to a non-...
Alexander Pruss's user avatar
8 votes
1 answer
518 views

What is the Turing degree associated with an ultrafilter $U$?

I asked Turing degree of a turing machine with access to an (arbitrary) nonstandard integer, not thinking about the possiblity that this could depend on the model used. The question was not formulated ...
Christopher King's user avatar
5 votes
3 answers
824 views

Turing degree of a turing machine with access to an (arbitrary) nonstandard integer

Let us consider Turing machines (or other Turing-complete model of computation) that, in addition to their regular input, are given some integer $H$, where $H$ is positive nonstandard. This means, in ...
Christopher King's user avatar
7 votes
1 answer
555 views

Are the definable hyper-reals, using quantifiers only over the standard reals and natural numbers, the same as the algebraic numbers?

This question arose today at Yevgeny Gordon's talk, "Will nonstandard analysis be the analysis of the future?" at the CUNY Logic Workshop. Here is my way of asking it. Consider the ordered real field ...
Joel David Hamkins's user avatar
20 votes
2 answers
977 views

Automorphisms of the hyperreals over the rationals and nontrivial automorphism groups

A classic result says the automorphism group of $\mathbb{R}$ (over $\mathbb{Q}$) is trivial. The proof is simple: every automorphism preserves squares, and hence fixes the positive reals, so it must ...
Brian Pinsky's user avatar
2 votes
1 answer
310 views

Is there a model of ZF+ACC where transfer fails for the definable hyperreals?

In 2003 Kanovei and Shelah constructed a definable hyperreal field. The ultrapower used exploits a fairly large index set so that it is clear that the usual proof of Los and transfer does not go ...
Mikhail Katz's user avatar
  • 15.8k
3 votes
1 answer
1k views

What is the modern consensus on the difficulty of infinitesimals?

At a related thread at MSE an expert in reverse mathematics noted that "As the modern consensus is that only nonstandard models have infinitesimals, it will be quite challenging to give a concrete ...
Mikhail Katz's user avatar
  • 15.8k

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