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2 votes
0 answers
73 views

Question related to number of distinct forcing extensions of a countable model

A bit of context: the below question is motivated by roughly the following scenario: we have some countable model $\mathcal{M}$, and want to “count” the number of functions/sets $f$ such that $\...
Oliver Korten's user avatar
17 votes
3 answers
1k views

Minimum transitive models and V=L

Is there a c.e. theory $T⊢\text{ZFC}$ in the language of set theory such that the minimum transitive model of $T$ exists but does not satisfy $V=L$? You may assume that ZFC has transitive models. ...
Dmytro Taranovsky's user avatar
5 votes
1 answer
245 views

Highly improper forcings

The following question comes from a typo in an old notebook of mine (I changed what I was calling my forcing notion partway through writing the definition of properness): Say that a forcing $\mathbb{P}...
Noah Schweber's user avatar
7 votes
1 answer
369 views

How hard is it to get "absolutely" no amorphous sets?

A beautiful and surprising (to me at least) result around the axiom of choice is that, while full $\mathsf{AC}$ is preserved by forcing, a model of $\mathsf{ZF}$ + "There are no amorphous sets&...
Noah Schweber's user avatar
10 votes
3 answers
925 views

Why can we assume a ctm of ZFC exists in forcing

Following Kunen's book, it makes clear that countable transitive models (ctm) exist only for a finite list of axioms of ZFC. So, why can we assume a ctm of the whole ZFC axioms exists and use it as ...
Guest's user avatar
  • 101
6 votes
1 answer
209 views

How often are forcing extensions of countable computably saturated models of $\mathsf{ZFC}$ computably saturated?

Recall that given a finite language $\mathcal{L}$, we say that an $\mathcal{L}$-structure is computably saturated (or recursively saturated) if for any computable set $\Sigma(\bar{x},y)$ of $\mathcal{...
James E Hanson's user avatar
2 votes
0 answers
183 views

Generalized models of set theory

The forcing method can be viewed as building a Boolean-valued model of set theory. Some generalizations include Heyting algebra/sheaf/lattice-valued model. However, it seems these generalizations are ...
Kushi's user avatar
  • 237
12 votes
1 answer
602 views

Can $\mathcal{L}_{\omega_1,\omega}$ detect $\mathcal{L}_{\omega_1,\omega}$-equivalence?

Roughly speaking, say that a logic $\mathcal{L}$ is self-equivalence-defining (SED) iff for each finite signature $\Sigma$ there is a larger signature $\Sigma'\supseteq\Sigma\sqcup\{A,B\}$ with $A,B$ ...
Noah Schweber's user avatar
5 votes
1 answer
260 views

Can the forcing-absolute fragment of SOL have a strong Lowenheim-Skolem property?

Previously asked and bountied at MSE: Let $\mathsf{SOL_{abs}}$ be the "forcing-absolute" fragment of second-order logic - that is, the set of second-order formulas $\varphi$ such that for ...
Noah Schweber's user avatar
7 votes
0 answers
283 views

Generic behavior of "polynomialish" models of $\mathsf{Q}$

(This question was originally asked and bountied at MSE - with different notation, some more explicit arguments, and topology in place of forcing.) Suppose $\mathcal{R}=(R_i)_{i\in\mathbb{N}}$ is a ...
Noah Schweber's user avatar
12 votes
2 answers
910 views

Is this definability principle consistent?

(Below I'm thinking only about computably axiomatizable set theories extending $\mathsf{ZFC}$ which are arithmetically, or at least $\Sigma^0_1$-, sound.) Say that a theory $T$ is omniscient iff $T$ ...
Noah Schweber's user avatar
7 votes
2 answers
673 views

Can second-order logic identify "amorphous satisfiability"?

Recall that a set is amorphous iff it is infinite but has no partition into two infinite subsets. I'm interested in the possible structure (in the sense of model theory) which an amorphous set can ...
Noah Schweber's user avatar
8 votes
1 answer
446 views

Intuition behind Boolean-valued models of set theory

$\DeclareMathOperator\Card{Card}$The book Forcing Eine Einführung in die Mathematik der Unabhängigkeitsbeweise by Hoffmann provides an intuition behind boolean valued models of set theory which I will ...
Bytegear's user avatar
  • 123
3 votes
1 answer
418 views

Forcing, a technical detail

In the snippet below from Shelah's book P&I Forcing, in the definition 5.2(2) I do not follow why in this sentence [naturally extended to include $N\prec (H(\mu^\dagger),\epsilon),\mu\in N$] $N$ ...
user2925716's user avatar
14 votes
1 answer
506 views

Is there an infinitary sentence which is absolutely not second-order expressible?

This is a "forcing-absolute" followup to this question, whose answer was largely unsatisfying. The question is: Suppose $V=L$. Is there an $\mathcal{L}_{\infty,\omega}$-sentence $\varphi$ ...
Noah Schweber's user avatar

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