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20 votes
2 answers
1k views

Non-definability of graph 3-colorability in first-order logic

What is a proof that graph 3-colorability is not definable in first order logic? Where did it first appear?
Leo Marcus's user avatar
3 votes
2 answers
261 views

Is every countable model of ZFC a subset of some parameter free definable pointwise-definable model of ZFC?

Is it consistent with $\sf ZFC + \text{ countable models of } ZFC \text { exist}$, that every countable model of $\sf ZFC$ is a subset of some parameter free definable pointwise-definable model of $\...
Zuhair Al-Johar's user avatar
3 votes
1 answer
152 views

If a theory speaks of sets that cannot be forced to be parameter free definable, then does this entail a large cardinal property?

If we say that an effectively generated first order theory $\sf T$ extends $\sf ZF$, such that every countable model of $\sf T$ doesn't have a class forcing extension that is pointwise definable. ...
Zuhair Al-Johar's user avatar
1 vote
1 answer
143 views

Is there a model of each of the following kinds of theories in the first transitive model of ZFC?

The question of whether the minimal transitive model $M$ of $\sf ZFC$ have a model of each consistent extension $\sf T$ of $\sf ZF$, is answered to the negative, basically because $M$ is countable and ...
Zuhair Al-Johar's user avatar
1 vote
1 answer
86 views

Are externally pointwise definable models of ZFC subject to the same limitations of the internally pointwise definable ones?

By pointwise definable models, it's meant that every element of those models is definable after a formula in a parameter free manner, but that defining formula is in the language of that model, i.e., ...
Zuhair Al-Johar's user avatar
7 votes
1 answer
448 views

Are no infinite subsets of the set of all propositional atoms definable in this structure, even with parameters?

I asked this on Math Stack Exchange, but apparently no one paid attention to it. So, I am asking it again, filling in the background necessary to understand it. Consider a countably infinite set $P$ ...
user107952's user avatar
  • 2,063
19 votes
1 answer
1k views

Is the theory of a partial order bi-interpretable with the theory of a pre-order?

A partial order relation $\leq$ on a set $A$ is a binary relation that is reflexive, transitive, and antisymmetric. A preorder relation $\unlhd$ (also sometimes known as a quasi order or pseudo order) ...
Joel David Hamkins's user avatar
12 votes
3 answers
865 views

Is there a simple instance of intransitivity for implicit definability?

This question continues the theme of some recent questions on implicit definability. A relation $R$ is implicitly definable in a first-order structure $M$ if there is a property $\varphi(\dot R)$, ...
Joel David Hamkins's user avatar
22 votes
1 answer
1k views

Is the set of primes implicitly definable from successor?

An earlier question by Joel David Hamkins asked whether multiplication is implicitly definable in the structure $(\mathbb{N},S)$ of the naturals with successor. Here $R$ is implicitly definable if ...
Geoffrey Irving's user avatar
44 votes
2 answers
4k views

Is multiplication implicitly definable from successor?

A relation $R$ is implicitly definable in a structure $M$ if there is a formula $\varphi(\dot R)$ in the first-order language of $M$ expanded to include relation $R$, such that $M\models\varphi(\dot R)...
Joel David Hamkins's user avatar
0 votes
1 answer
124 views

An infinite Leibnizian structure in a finite language with precisely $n$ definable elements

This question was inspired by Joel David Hamkins's excellent question on Leibnizian structures with no definable elements. Let $n$ be a positive integer. Is there an infinite structure in a finite ...
user107952's user avatar
  • 2,063
10 votes
1 answer
481 views

Definable constructions in o-minimal geometry

Recently I've been working with o-minimal expansions of $(\mathbb{R},\times,+)$, and I want to work "internally" to the language of o-minimal sets instead of working with "definable ...
Hunter Spink's user avatar
4 votes
1 answer
284 views

What is the lowest complexity definition of $\mathbb{Z}$ in an infinite algebraic extension of $\mathbb{Q}$?

In 2009, Jochen Koenigsmann showed that $\mathbb{Z}$ is universally definable in the field $\mathbb{Q}$. And in 2012, Jennifer Park proved a result which implies that $\mathbb{Z}$ is $\exists\forall$-...
Keshav Srinivasan's user avatar
8 votes
1 answer
247 views

What is the lowest complexity definition of $\mathbb{Z}$ in an infinite extension of $\mathbb{Q}$

In 2009, Jochen Koenigsmann showed that $\mathbb{Z}$ is universally definable in the field $\mathbb{Q}$. And in 2012, Jennifer Park proved a result which implies that $\mathbb{Z}$ is $\exists\forall$-...
Keshav Srinivasan's user avatar
10 votes
1 answer
400 views

Is $\mathbb{Z}$ universally definable in any number fields other than $\mathbb{Q}$?

In 2009, Jochen Koenigsmann showed that $\mathbb{Z}$ is universally definable in the field $\mathbb{Q}$. My question is, are there any other number fields in which $\mathbb{Z}$ is universally ...
Keshav Srinivasan's user avatar

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