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2 votes
0 answers
204 views

Is there a computable model of HoTT?

Among the various models of homotopy type theory (simplicial sets, cubical sets, etc.), is there a computable one? Can the negative follow from the Gödel-Rosser incompleteness theorem? If there is no ...
user avatar
1 vote
1 answer
551 views

Natural Numbers

Let $L$ be a countable language and $M$ be a model of $L^N$ (the realization of $L$ in the natural numbers $N$) in which every recursive unary relation is expressible. Show that $M$ is not recursive.
Speltzu's user avatar
  • 265
3 votes
0 answers
140 views

Lindström's theorem part 2 for non-relativizing logics

By "logic" I mean the definition gotten by removing the relativization property from "regular logic" — see e.g. Ebbinghaus/Flum/Thomas — and adding the condition that for every ...
Noah Schweber's user avatar
3 votes
0 answers
94 views

Comparing computable structures via Kleene and Skolem

Below, by "structure" I mean "computable structure in a finite language with domain $\omega$," and by "sentence" I mean "finitary first-order sentence containing no ...
Noah Schweber's user avatar
0 votes
0 answers
176 views

Can a model of "true computation" exist? What would be its consequences?

Analogous to the model of True Arithmetic, the model of "True Computation" is defined to be the set of all true first-order statements about Turing machines i.e. answers to elementary ...
symmetrickittens's user avatar
10 votes
2 answers
441 views

Is the set of permissible numbers of models of various cardinalities computable?

This question arose in the comments to this question. Let $X$ be the set of pairs $(m,k)$ such that there is some (consistent complete countable first-order) theory $T$ with exactly $m$ models of size ...
Noah Schweber's user avatar
7 votes
0 answers
108 views

How tightly are decidability and "induction-completeness" linked?

It is known that there are a number of expansions of the structure $\mathfrak{N}:=(\mathbb{N};+)$ which are decidable (= have computable theories); one such example is the expansion by a predicate ...
Noah Schweber's user avatar
6 votes
0 answers
121 views

An analogue of Scott sentences in the (mostly) computable realm?

Below, "structure" means "computable structure in a computable language." In particular, we do distinguish between isomorphic copies of the same structure. Let $\mathcal{L}_{\...
Noah Schweber's user avatar
5 votes
1 answer
461 views

How to solve this exercise about large countable ordinals?

In this note (Notes on Higher Type ITTM-recursion, 2021) written by Philip Welch, I'm trying to solve exercise 3.5(i), but I don't know how to solve it. The problem is: assume that $L_{\gamma_0}<_{...
Reflecting_Ordinal's user avatar
5 votes
2 answers
273 views

Is the usual enumeration of $\mathsf{PA}$ "minimal for consistency strength"?

This question is about a technical imprecision which is easily avoidable but whose details I'd like to understand better. When we refer to "the consistency strength of $\mathsf{PA}$" (say) ...
Noah Schweber's user avatar
6 votes
1 answer
547 views

Parameter-free effective cardinals

In the paper "Effective cardinals and determinacy in third order arithmetic" by Juan Aguilera, effective cardinals is defined. I'm curious about its little variation, parameter-free ...
Reflecting_Ordinal's user avatar
0 votes
0 answers
63 views

First-order logics expressively equivalent to the computable languages

There is a really nice theorem that the subsets of $(\Sigma^*, =_{el}, \preceq, (S_a)_{a \in \Sigma})$ definable in first-order logic are exactly the regular sets. Where: $\Sigma^*$ is the set of ...
TomKern's user avatar
  • 429
6 votes
1 answer
209 views

How often are forcing extensions of countable computably saturated models of $\mathsf{ZFC}$ computably saturated?

Recall that given a finite language $\mathcal{L}$, we say that an $\mathcal{L}$-structure is computably saturated (or recursively saturated) if for any computable set $\Sigma(\bar{x},y)$ of $\mathcal{...
James E Hanson's user avatar
6 votes
0 answers
205 views

Fragments of infinitary logic with a weak definability property

For a countable admissible ordinal $\alpha$, let $\mathcal{L}_\alpha=\mathcal{L}_{\infty,\omega}\cap L_\alpha$ and let $\equiv_\alpha$ be the corresponding elementary equivalence relation. Say that ...
Noah Schweber's user avatar
4 votes
1 answer
420 views

Alternative proof of Tennenbaum's theorem

The standard proof of Tennenbaums's theorem uses the existence of recursively enumerable inseparable sets and is presented e.g. in Kaye [1, 2], Smith [3]. In the following, $\mathcal{M}$ will always ...
Léreau's user avatar
  • 211

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