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4 votes
1 answer
330 views

GCD in $\mathbb{F}_3[T]$ with powers of linear polynomials

This is a continuation of my previous question on $\gcd$s of polynomials of type $f^n - f$. Let us call $n > 1$ simple at a prime $p$ when $p-1 \mid n-1$ but $p^k - 1 \not\mid n-1$ for all $k > ...
Martin Brandenburg's user avatar
2 votes
0 answers
116 views

When $\gcd(P(x),Q(x))\bmod R(x)=\gcd(P(x) \bmod R(x),Q(x) \bmod R(x))$?

Let's $P,Q\in\mathbb K[x]$, with $\mathbb K$ a finite field. On what necessary and sufficient condition on $R \in \mathbb K[x]$ is it : $\gcd(P(x),Q(x))\bmod R(x)=\gcd(P(x) \bmod R(x),Q(x) \bmod R(x))...
Dattier's user avatar
  • 3,824
10 votes
1 answer
320 views

Proving that polynomials belonging to a certain family are reducible

In an article, I've found the following result. Unfortunately, it was derived from a general, somewhat complicated theory, that would be cumbersome for this result alone. Assume that $\mathbb F_p$ is ...
MikeTeX's user avatar
  • 687
7 votes
1 answer
979 views

Polynomials which are functionally equivalent over finite fields

Recall that two polynomials over a finite field are not necessarily considered equal, even if they evaluate to the same value at every point. For example, suppose $f(x) = x^2 + x + 1$ and $g(x) = 1$. ...
Gautam's user avatar
  • 1,703
5 votes
1 answer
217 views

Intrinsic characterisation of a class of rings

This may be well known, but I was unable to find an answer browsing literature. Let us temporarily call a commutative (unital) ring $R$ an O-ring if there exists an integer $n \ge 1$, a local field of ...
Keivan Karai's user avatar
  • 6,162
11 votes
1 answer
472 views

Greatest common divisor in $\mathbb{F}_p[T]$ with powers of linear polynomials

Let $n>1$ and $p$ be an odd prime with $p-1 \mid n-1$ such that $p^k - 1 \mid n-1$ does not hold for any $k>1$. Notice that, since $p-1 \mid n-1$, we have $T^p - T \mid T^n-T$ in $\mathbb{F}_p[T]...
Martin Brandenburg's user avatar
4 votes
0 answers
188 views

Chevalley-Warning for finite rings: the degree of a non-polynomial

$\def\F{\mathbb F}$ $\def\Z{\mathbb Z}$ One reason that Chevalley-Warning theorem is that amazingly useful is the fact that for a finite field $\F$, any function from $\F^n$ to $\F$ is a polynomial. ...
Seva's user avatar
  • 23k
1 vote
1 answer
784 views

Trace 0 and Norm 1 elements in finite fields

Let $\mathbb{F}_{q^\ell}/\mathbb{F}_{q}$ be the extension of finite filed $\mathbb{F}_{q}$, where $\ell$ be a odd prime and $(\neq q)$. Take $\zeta\in\mathbb{F}_{q^\ell}$. Does there exist different $...
sampath's user avatar
  • 255
15 votes
2 answers
1k views

Can you use Chevalley‒Warning to prove existence of a solution?

Recall the Chevalley‒Warning theorem: Theorem. Let $f_1, \ldots, f_r \in \mathbb F_q[x_1,\ldots,x_n]$ be polynomials of degrees $d_1, \ldots, d_r$. If $$d_1 + \ldots + d_r < n,$$ then the ...
R. van Dobben de Bruyn's user avatar
18 votes
5 answers
7k views

Is $x^p-x+1$ always irreducible in $\mathbb F_p[x]$?

It seems that for any prime number $p$ and for any non-zero element $a$ in the finite field $\mathbb F_p$, the polynomial $x^p-x+a$ is irreducible over $\mathbb F_p$. (It is of course obvious that ...
Roland Bacher's user avatar
4 votes
1 answer
2k views

Irreducibility of some trinomials modulo $p$

Let $n>1$ be an integer. An old result of Selmer, See Theorem 1, page 289 in http://www.mscand.dk/article.php?id=1472, (If the link does not work try googling: ...
Luis H Gallardo's user avatar