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4 votes
0 answers
173 views

About the structure of smooth automorphic forms

Recently I read Prof. Cogdell's notes: Lectures on L-functions, Converse Theorems, and Functoriality for $GL_n$. (Co) In chap.2.3, the conception of smooth automorphic forms is introdued. Explicitly, ...
Adjoint Functor's user avatar
3 votes
0 answers
77 views

Unitary with entries $(i,j)$ only on equidistant lattice points $\|i-j\|^2 = c^2 \in \mathbb{N}$

My research needs help in finding examples of unitary matrices $U$ which have entries \begin{align} U_{ij} = \begin{cases} \alpha_{ij}, \ \text{ if } \|i-j\|^2 = c^2 \\ 0 , \text{ otherwise} \end{...
moji's user avatar
  • 41
5 votes
0 answers
117 views

Good (Sidon) Approximation of "Bumps"

Given a rational point $p\in S^1$ and a continuous function $f:S^1\rightarrow \mathbb C$, we say that $f$ is an $\epsilon$-bump around $p$ (for some $\epsilon>0$) if $f(p)=1,|f|_{\infty}\leq 1+\...
user3293260's user avatar
2 votes
1 answer
883 views

Fourier transform of the von Mangoldt function?

Wikipedia states under the entry for the von Mangoldt function: The Fourier transform of the von Mangoldt function gives a spectrum with spikes at ordinates equal to imaginary part of the Riemann ...
Tom Copeland's user avatar
  • 10.2k
2 votes
0 answers
127 views

Wiener-Ikehara Theorem and Signal Processing

I am trying to understand the Wiener-Ikehara Tauberian theorem which can be a step to understanding the prime number theorem. Let $$ \hat{a}(s) = \int_0^\infty e^{-us}\, da(u) $$ with $a(u)$ some ...
john mangual's user avatar
  • 22.7k
10 votes
2 answers
892 views

Isomorphisms between spaces of test functions and sequence spaces

I am in the process of writing some self-contained notes on probability theory in spaces of distributions, for the purposes of statistical mechanics and quantum field theory. Perhaps the simplest ...
Abdelmalek Abdesselam's user avatar
7 votes
3 answers
1k views

A Question concerning the Fourier Transform of $\mathbb{R}$

Consider the classical Schwartz space $\mathcal{S}(\mathbb{R})$ together with the Fourier transform $\mathcal{F} : \mathcal{S}(\mathbb{R}) \rightarrow \mathcal{S}( \mathbb{R})$. Consider the subspace ...
Marc Palm's user avatar
  • 11.1k