Skip to main content
replaced http://cstheory.stackexchange.com/ with https://cstheory.stackexchange.com/
Source Link

The numerical coincidence

$\displaystyle \frac{1663e^2}{3} \approx 2^{12}$.

showed up in a comment of this mostly-unrelated questionthis mostly-unrelated question.

Numerically, it's not a surprise that $e^2$ is close to a rational number whose numerator and denominator are in this range — similarly good approximations to most numbers can be obtained by truncating the continued fraction at the desired level of accuracy. What's much more of a surprise to me is the appearance of a 12th power in this expression. Is there a good explanation for having such a smooth number here? E.g. see the j-invariant explanation for Ramanujan's observation that

$e^{\pi\sqrt{163}}$

is close to an integer, or the Pisot number explanation for the fact that even powers of the golden ratio are close to integers.

The numerical coincidence

$\displaystyle \frac{1663e^2}{3} \approx 2^{12}$.

showed up in a comment of this mostly-unrelated question.

Numerically, it's not a surprise that $e^2$ is close to a rational number whose numerator and denominator are in this range — similarly good approximations to most numbers can be obtained by truncating the continued fraction at the desired level of accuracy. What's much more of a surprise to me is the appearance of a 12th power in this expression. Is there a good explanation for having such a smooth number here? E.g. see the j-invariant explanation for Ramanujan's observation that

$e^{\pi\sqrt{163}}$

is close to an integer, or the Pisot number explanation for the fact that even powers of the golden ratio are close to integers.

The numerical coincidence

$\displaystyle \frac{1663e^2}{3} \approx 2^{12}$.

showed up in a comment of this mostly-unrelated question.

Numerically, it's not a surprise that $e^2$ is close to a rational number whose numerator and denominator are in this range — similarly good approximations to most numbers can be obtained by truncating the continued fraction at the desired level of accuracy. What's much more of a surprise to me is the appearance of a 12th power in this expression. Is there a good explanation for having such a smooth number here? E.g. see the j-invariant explanation for Ramanujan's observation that

$e^{\pi\sqrt{163}}$

is close to an integer, or the Pisot number explanation for the fact that even powers of the golden ratio are close to integers.

rewrite to avoid inane answers
Source Link
David Eppstein
  • 18.5k
  • 2
  • 54
  • 127

The numerical coincidence

$\displaystyle 1663 \approx \frac{3\times 2^{12}}{e^2}$$\displaystyle \frac{1663e^2}{3} \approx 2^{12}$.

showed up in a comment of this mostly-unrelated question.

Numerically, it's not a surprise that $e^2$ is close to a rational number whose numerator and denominator are in this range — similarly good approximations to most numbers can be obtained by truncating the continued fraction at the desired level of accuracy. What's much more of a surprise to me is the appearance of a 12th power in this expression. Is there a good explanation for this, ehaving such a smooth number here? E.g. likesee the j-invariant explanation for Ramanujan's observation that

$e^{\pi\sqrt{163}}$

is close to an integer, or likethe Pisot number explanation for the fact that even powers of the golden ratio are close to integers?.

The numerical coincidence

$\displaystyle 1663 \approx \frac{3\times 2^{12}}{e^2}$.

showed up in a comment of this mostly-unrelated question.

Is there a good explanation for this, e.g. like the j-invariant explanation for Ramanujan's observation that

$e^{\pi\sqrt{163}}$

is close to an integer, or like the fact that even powers of the golden ratio are close to integers?

The numerical coincidence

$\displaystyle \frac{1663e^2}{3} \approx 2^{12}$.

showed up in a comment of this mostly-unrelated question.

Numerically, it's not a surprise that $e^2$ is close to a rational number whose numerator and denominator are in this range — similarly good approximations to most numbers can be obtained by truncating the continued fraction at the desired level of accuracy. What's much more of a surprise to me is the appearance of a 12th power in this expression. Is there a good explanation for having such a smooth number here? E.g. see the j-invariant explanation for Ramanujan's observation that

$e^{\pi\sqrt{163}}$

is close to an integer, or the Pisot number explanation for the fact that even powers of the golden ratio are close to integers.

added 3 characters in body
Source Link
David Eppstein
  • 18.5k
  • 2
  • 54
  • 127

The numerical coincidence

$\displaystyle 1663 \approx \frac{3\times 2^{12}}{e^2}$.

showed up in a comment of this mostly-unrelated question.

Is there a good explanation for this, e.g. like the j-invariant explanationj-invariant explanation for Ramanujan's observation that

$e^{\pi\sqrt{163}}$

is close to an integer, or like the fact that even powers of the golden ratio are close to integers?

The numerical coincidence

$\displaystyle 1663 \approx \frac{3\times 2^{12}}{e^2}$.

showed up in a comment of this mostly-unrelated question.

Is there a good explanation for this, e.g. like the j-invariant explanation for Ramanujan's observation that

$e^{\pi\sqrt{163}}$

is close to an integer, or like the fact that powers of the golden ratio are close to integers?

The numerical coincidence

$\displaystyle 1663 \approx \frac{3\times 2^{12}}{e^2}$.

showed up in a comment of this mostly-unrelated question.

Is there a good explanation for this, e.g. like the j-invariant explanation for Ramanujan's observation that

$e^{\pi\sqrt{163}}$

is close to an integer, or like the fact that even powers of the golden ratio are close to integers?

Source Link
David Eppstein
  • 18.5k
  • 2
  • 54
  • 127
Loading