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Oct 20, 2011 at 13:00 comment added Ramiro de la Vega Just for the record, the standard proof of the more general Konig's theorem ($\kappa^{cof(\kappa)}>\kappa$ for $\kappa$ any aleph) doesn´t use AC (it is essentially the same proof that Joel already gave).
Oct 20, 2011 at 8:33 vote accept Asaf Karagila
Oct 20, 2011 at 8:33 comment added Asaf Karagila Thanks a lot, Joel. I swear I read somewhere that in the Feferman-Levy model $2^\omega=\omega_1$. I can't find it, and the proofs you and Andres gave convince me that it was probably in a dream.
Oct 20, 2011 at 3:41 comment added Joel David Hamkins This argument is essentially the same as the argument that Andres gave in the comments above, but it seems to answer the whole question, and not just the issue about the reals being a countable union of countable sets. The proof shows more generally that the continuum, if well-orderable, cannot have countable cofinality, even in ZF.
Oct 20, 2011 at 3:34 history edited Joel David Hamkins CC BY-SA 3.0
edited body; added 4 characters in body
Oct 20, 2011 at 3:28 history answered Joel David Hamkins CC BY-SA 3.0