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  • $\begingroup$ Isn't $dv(\kappa)=\kappa$ implied by GCH? $\endgroup$ Commented May 13, 2014 at 7:20
  • $\begingroup$ @NoahS, that's VERY possible. What's your reasoning? $\endgroup$ Commented May 13, 2014 at 7:25
  • $\begingroup$ It's late, so I might just be wrong, but I've posted it as an answer and it passes the smell test for me. $\endgroup$ Commented May 13, 2014 at 7:31