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S Oct 6, 2020 at 23:59 history suggested HDB CC BY-SA 4.0
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Oct 6, 2020 at 22:07 review Suggested edits
S Oct 6, 2020 at 23:59
Aug 8, 2012 at 21:36 comment added Gérard Lang This is not an answer, but a repetition of my linked questions already stated in <mathoverflow.net/questions/28389>. 1/ Is it possible to dispense with axiom 4 (the axiom of pairing from ZF(C)) to develop the Tarski-Grothendieck (TG) set theory? 2/ Does anybody know how to prove the 16 equivalences between conditions of axioms A and A' of Tarski ? Gérard Lang
Jul 23, 2012 at 20:41 vote accept Mike Battaglia
Jul 23, 2012 at 6:55 history edited Mike Battaglia CC BY-SA 3.0
changed axiom "C" to "Ca" to not conflict with C being the axiom of choice
Jul 23, 2012 at 6:54 comment added Mike Battaglia Fair enough. I'll change it to "Ca".
Jul 22, 2012 at 18:58 comment added John Bentin "C" already denotes the axiom of choice, so it's not the best abbreviation for another axiom.
Jul 22, 2012 at 1:10 answer added Trevor Wilson timeline score: 21
Jul 22, 2012 at 0:38 history asked Mike Battaglia CC BY-SA 3.0