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2 votes
1 answer
257 views

Experimental`CreateNumericalFunction

When working with a Compile function I can specify if a given argument is a matrix, a vector or a scalar. For instance, something like: ...
user12588's user avatar
  • 535
6 votes
1 answer
166 views

Is it possible to make listable Experimental`NumericalFunction?

I have been playing a bit with the undocumented function Experimental`CreateNumericalFunction and I wanted to know if somebody found a way to make generated ...
user12588's user avatar
  • 535
11 votes
0 answers
184 views

How to modify NDSolve`StateData without crashing the kernel?

Probably a hard question, but it's better to cry out loud. Reminded by Chris K, I noticed my fix function has been broken since v11.3. After some checking, I ...
xzczd's user avatar
  • 67.1k
16 votes
1 answer
653 views

What happened to SequenceLimit?

In older versions of Mathematica, there was a function called SequenceLimit that allowed taking the limit of a numerical sequence. It is useful for speeding up the ...
Chris Chiasson's user avatar
14 votes
1 answer
304 views

How is the Hessian computed using ``Experimental`NumericalFunction``?

Here and here it was explained how to use Experimental`NumericalFunction to compute the Hessian of a numerical function. I would like to know how this undocumented ...
Valerio's user avatar
  • 1,982
26 votes
4 answers
727 views

How does Internal`CompareNumeric work?

In this answer, Oleksandr R. mentioned an undocumented function Internal`CompareNumeric and briefly explained its usage as follows: ...
xzczd's user avatar
  • 67.1k
10 votes
1 answer
317 views

Can Someone Please Explain Internal`$SameQTolerance?

If I input Internal`$SameQTolerance (* output = 0.30103 *) which is the approximation of Log[10,2], or ...
user155812's user avatar
47 votes
2 answers
2k views

How to work with Experimental`NumericalFunction?

This question is intimately connected with previous one: "How to create internally optimized expression for computing with high WorkingPrecision?" Oleksandr R. correctly states in the comment: A ...
Alexey Popkov's user avatar