Skip to main content

All Questions

3 votes
2 answers
222 views

Can Mathematica simplify an ordinary differential equation (ODE) by assuming a power series solution and obtain the recurrence relation?

I have an ordinary differential equation and want to solve it using power series as ψ[x_] = Sum[Subscript[a, n] x^n, {n, 0, ∞}] to obtain the recurrence relation ...
PhysFan's user avatar
  • 63
0 votes
0 answers
82 views

How to do this recursion relation in Mathematica effectively?

I have a function $h_{\Delta,l}(r,\eta)$ satisfying \begin{equation} h_{\Delta,l}(r,\eta)=\tilde{h}_{l}(r,\eta)+\sum_{k}\frac{c(k)}{\Delta-(1-l-k)}r^{k}h_{1-l+k,l+k}(r,\eta) \end{equation} where $k$ ...
Vayne's user avatar
  • 101
0 votes
1 answer
79 views

Trouble while trying to re-run open source code

I am a physics student and this is my first time working with Mathematica. I am trying to run the notebook mentioned here, titled "Amplification factors of the superradiant scattering of a ...
newtothis's user avatar
1 vote
2 answers
156 views

Recursive sequence with RecurenceTable

I want to compute elements of a recursive sequence and use them as coefficients of a power series. However, the (i+1)-th element depends on all previous elements. Writing this as a sum in ...
VN23's user avatar
  • 123
0 votes
0 answers
63 views

Recurrence relation of coeeficients of power series solution to DE

Say I have a DE $$ -\phi \left(\phi \left(\left(6975 \phi ^2-3704 \phi +160\right) \omega '(\phi )+\phi \left(\left(6975 \phi ^2-4688 \phi +266\right) \omega ''(\phi )+\phi \left(2 \left(...
Bernoulli's user avatar
  • 203
0 votes
2 answers
404 views

Getting the coefficients of a series that solves a differential equations

I have an example from Stewart's Calculus where the equation $y'' + y = 0$ is solved using power series. The equation ...
BenNevis's user avatar
1 vote
3 answers
165 views

Why doesn't Mathematica evaluate the series with recursion relationship as expected?

I define a series $dg(i)$ as the $i$th derivative of a function $g[t]$ for $i>0$ and known the first term $dg(1)=(t-x)g(t)$. In mathematica, the code is: ...
tanghe2014's user avatar
2 votes
1 answer
356 views

Solving for the recursion relation for the expansion coefficients of the asymptotic expansion of an ODE

I want to solve for the asymptotic solution of the following differential equation $$ \left(y^2+1\right) R''(y)+y\left(2-p \left(b_{0} \sqrt{y^2+1}\right)^{-p}\right) R'(y)-l (l+1) R(y)=0$$ as $y\...
user583893's user avatar
4 votes
2 answers
228 views

Problems with ContinuedFractionK

I am interested in calculating the following series $$ \sum_{k=0}^{+\infty}{ \frac{ x^k }{\, a (a+1) \cdots (a+k) \,} } $$ using this continued fraction (I expect) equivalent form: $$ \cfrac{1}{a + ...
Vicent's user avatar
  • 1,101
6 votes
3 answers
1k views

How can I make Mathematica return a series expansion in the form $\sum_{j=0}^\infty \dots$ instead of $a_0 + a_1x^1 + \dots + a_{n-1}x^{n-1}+ O(x^n)$

I have a function $$\phi(x) = \sqrt{(x-t)^2 + c^2},$$ and I want an asymptotic expression for it as $x \to \infty$. Using the following code I can calculated such an expression: ...
ManUtdBloke's user avatar
3 votes
2 answers
708 views

How to simplify output of Series?

The command Series[Sum[Sum[1/(a*b), {b, a, 3 a}], {a, 1, N/Sqrt[3]}, Assumptions -> N > 0], {N, Infinity, 1}] produces a somewhat complicated answer <...
user64494's user avatar
  • 27.3k
4 votes
1 answer
424 views

Computing a series in terms of exponential function

Is there any way to compute the following series in terms of exponential function ? $$\sum_{k=0}^\infty Y_1(k)\;x^k$$ where $$Y_1(k) = \frac{(k - 1)!}{k!}Y_3(k - 1)$$ $$Y_2(k) = \frac{(k - 1)!}{k!}...
Angel's user avatar
  • 155