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Tagged with expression-construction algorithm
3
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8
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Ragged Diamonds
diamond[n_Integer] :=
Table[1, {#}] & /@ (Range[n]~ Join~Range[n - 1, 1, -1])
diamond[5] // MatrixForm
How could a more functional, "tablefree", solution ...
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19
votes
11
answers
2k
views
Efficient way to build a certain square matrix
For odd n I'm looking for a short and swift way to construct with (f.e.)
n = 3
n = 11
<...
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