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    $\begingroup$ fyi, you can just do dt = $MachineEpsilon; and it works also. $\endgroup$
    – Nasser
    Commented Apr 2 at 7:23
  • $\begingroup$ Thanks so much. Now I'm thinking can we get an analytic expression from this numeric solution? for instance by making fitting .. But can be this done with two variables $k$ and $t$? @UlrichNeumann $\endgroup$
    – Dr. phy
    Commented Apr 2 at 10:38
  • $\begingroup$ @Dr.phy You need an analytical formula? If not you can use X[k][t] like a build in function $\endgroup$
    – Ulrich Neumann
    Commented Apr 2 at 17:17
  • $\begingroup$ I'm asking can we get an analytic formula from this numerical solution. @UlrichNeumann $\endgroup$
    – Dr. phy
    Commented Apr 3 at 4:27
  • $\begingroup$ @UlrichNeumann. Could you look at this thread pls? mathematica.stackexchange.com/questions/301410/… $\endgroup$
    – Dr. phy
    Commented Apr 3 at 20:40