Skip to main content

All Questions

0 votes
2 answers
162 views

Pumps' geometric similarity

Given two pumps that are similar : $H_1=70-1.41x10^{-3}Q_1^2$ $H_2=100-1.1x10^{-3}Q_2^2$ Find the geometric scale : $\frac{D1}{D2}= ?$ I am also given maximum efficiency = 1. I tried solving but I got ...
Mather 's user avatar
  • 131
1 vote
1 answer
285 views

Why is the head loss in submerged pipe is 0

Looking at this question : Point C head loss is 0 according to the author Bottom right Can’t understand why , any good explanation for this claim ? Look at page 33 at the top
Mather 's user avatar
  • 131
-1 votes
1 answer
547 views

Head loss for T junction diverging water pipes

I am writing to ask for help with a T-junction pipe problem. Attached picture shows the pipe configuration. The schematic shows a large pipe with ID 16.5mm and smaller 4mm ID tubes connected to it. ...
Limpeh's user avatar
  • 1
0 votes
1 answer
390 views

Determining the headloss according to Darcy-Weisbach with pipes in parallel and series

Given the following situation: Pipe A and B have a known and identical length and diameter, and are in parallel. I'm assuming the flow trough pipes A and B are also identical, as is the roughness of ...
mcdesign's user avatar
1 vote
0 answers
339 views

Determining the Steady Discharge Between Two Reservoirs

A uniform pipeline, $5km$ in length, $100mm$ in diameter and with a roughness size of $0.03mm$, conveys water between two reservoirs. The difference in water level between the reservoirs is $...
Jake Wrightson's user avatar
0 votes
2 answers
642 views

Darcy-Weisbach Equation

I've come across two forms of the Darcy-Weisbach Equation, and each one seems to yield a different result when I am solving for $Q$ (flow). $$h_{f}=\frac{\lambda Lv^{2}}{2gD}$$ $$h_{f}=\frac{f LQ^{...
Tino M's user avatar
  • 41