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Apr 6 at 13:56 comment added Tim Williams The zener diode drops a ~fixed voltage when reverse biased, and there is a negative supply through a resistor for that bias; I'm not sure what else to say, it's an elementary connection. Perhaps you would find other questions on DC circuit analysis, diode and zener operation, fruitful?
Apr 6 at 7:49 comment added Chris95 Hello Mr.Williams, Yes i accepted the answer. I wanted to know how exactly we get a level shift.The RC circuit is an integrator. we have a -2.5V source and zenner diode.How exactly the Zenner diode makes the shifting of the pulse? Thanks.
Apr 4 at 12:42 vote accept Chris95
Apr 4 at 11:27 comment added Tim Williams I'm not sure what you're asking. Impedance matching isn't much of an issue here. Perhaps you mean in relation to some alternative arrangement? But what is not clear. Anyway, if I've answered your question as asked, an upvote and answer accept are appreciated; see: What should I do when someone answers my question?
Apr 4 at 11:03 comment added Chris95 Hello Mr.Williams ,given the section between point A to B. i know that we could do level shifter by doing simple voltage divider. however there is an impedance matching issue with the next stage.If i am correct could you please give me an intuition regarding why the impedace after point B matching the impedance before point B?
Apr 3 at 9:28 comment added Tim Williams Is it not this? i.sstatic.net/pYP7n.png
Apr 3 at 9:25 comment added Chris95 Hello Tim, I want to simulate the level shifter part from points A to B however i dont know what input pulse its intended for and what output value it supposed to produce on point B. Could you please say what input signal to use and what output value on point B should i expect on the otput? Thanks.
Apr 2 at 18:14 comment added Tim Williams That's the Darlington emitter follower part.
Apr 2 at 17:33 comment added Chris95 Hello Tim, so between A and B is a level shifter. what is the analog logic of the part show between the two arrows in the attached link? ibb.co/Rv19L07
Mar 31 at 1:15 comment added Tim Williams There is no logic function, simply a level shift. You can simulate the circuit to see voltages. LM4040 is a 2.5V regulator that has been replaced here with a voltage source.
Mar 30 at 19:12 comment added Chris95 Hello Mr. Williams, point A is a pulse of 0-3.3V at 120ns.I am trying to understand and simulate each step. given my original circuit could you please explain what is the logic from point A to B? they have an intresting diode in parralel with capacitor, and some things near the -2.5V power supply. whatis the logic in that?Thanks.
Mar 30 at 15:26 history answered Tim Williams CC BY-SA 4.0