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Oct 24, 2023 at 14:45 comment added glen_geek @MichalPodmanický crudely estimates charging time after the battery is connected. At the moment that it connects, consider the boost converter completely discharged. No doubt, it contains a reservoir input capacitance that will charge with a surge - the battery's 3 ohm resistance is significant here (but it will be a very short charge period compared with 3 seconds). You also might investigate how the boost converter limits charging current to 50mA.
Oct 24, 2023 at 14:04 answer added Andy aka timeline score: 0
Oct 24, 2023 at 13:46 comment added Michal Podmanický At worst case the power on output is 150.50mA=7.5W , If you load the battery with 7.5W the the 3ohms internal resistance is still insignificant.
Oct 24, 2023 at 13:40 comment added winny The ESR of the battery will eat up compliance voltage of the boost converter, but given that the boost has enough umpf to overcome it and keeps CC, it won’t affect your charging except for the very last ~1 % (in CV).
Oct 24, 2023 at 13:39 comment added Michal Podmanický It doesn’t until the resistance is extremely huge.
Oct 24, 2023 at 13:38 history edited winny CC BY-SA 4.0
Please start each sentence with capital letter.
Oct 24, 2023 at 12:55 comment added Ahmed Mohamed Hassan @MichalPodmanický so the internal resistor of battery has no effect on the cap.?
Oct 24, 2023 at 12:00 comment added Michal Podmanický For raw estimation of charging time you can use formula ic=C.dV/dt ,so t=CV/I= 1m.150/50m=3sec. However you don’t know how converter behaves during charging so 3sec is just raw value considering 50mA charging current.
Oct 24, 2023 at 11:45 comment added Hearth Whatever impedance you measured between the output terminals is meaningless. This is going to depend on the characteristics of the boost converter that you haven't shown--soft-start features, overcurrent features, that sort of stuff.
Oct 24, 2023 at 11:42 history asked Ahmed Mohamed Hassan CC BY-SA 4.0