Can I use a simple LM7805 for my beeper hobby circuit that monitors a 30 V battery?
The load current doesn't exceed 50 mA. It seems the IC will dissipate (30-5)*50 mA = 1.25 W worst case.
Will the IC survive?

(As of now I'm using a buck converter and it's taking lot of space; since the load is just 50 mA, I realized I could simply use a linear regulator instead)

Appreciate simple alternatives to convert 30 V to 5 V at 50 mA...

One idea:
I have a lot of 16 V 47 uF capacitors.
So can I put two 16 V capacitors in series and connect the combination to 30 V supply in parallel.
Then take the output 15 V from the middle and feed it to LM7805 input.
Will this work?

Can I use a simple LM7805 for my beeper hobby circuit that monitors a 30 V battery?
The load current doesn't exceed 50 mA. It seems the IC will dissipate (30-5)*50 mA = 1.25 W worst case.
Will the IC survive?

(As of now I'm using a buck converter and it's taking lot of space; since the load is just 50 mA, I realized I could simply use a linear regulator instead)

Appreciate simple alternatives to convert 30 V to 5 V at 50 mA...

One idea:
I have a lot of 16 V 47 uF capacitors.
So can I put two 16 V capacitors in series and connect the combination to 30 V supply in parallel.
Then take the output 15 V from the middle and feed it to LM7805 input.
Will this work?

Min voltage of battery is 22.5 V and max is 29.2 V. This circuit operates on my scooter battery.

Can I use a simple LM7805 for my beeper hobby circuit that monitors a 30V battery  ?
The load current doesn't exceed 50mA
It seems the IC will dissipate (30-5)*50mA = 1.25W worst case.
Will the IC survive?

(As of now I'm using a buck converter and it's taking lot of space; since the load is just 50mA, I realized I could simply use a linear regulator instead)

Appreciate simple alternatives to convert 30V to 5V 50mA...

One idea:
I have a lot of 16V 47uF capacitors.
So can I put two 16V capacitors in series and connect the combination to 30V supply in parallel.
Then take the output 15V from the middle and feed it to LM7805 input.
Will this work?

Can I use a simple LM7805 for my beeper hobby circuit that monitors a 30 V battery?
The load current doesn't exceed 50 mA. It seems the IC will dissipate (30-5)*50 mA = 1.25 W worst case.
Will the IC survive?

(As of now I'm using a buck converter and it's taking lot of space; since the load is just 50 mA, I realized I could simply use a linear regulator instead)

Appreciate simple alternatives to convert 30 V to 5 V at 50 mA...

One idea:
I have a lot of 16 V 47 uF capacitors.
So can I put two 16 V capacitors in series and connect the combination to 30 V supply in parallel.
Then take the output 15 V from the middle and feed it to LM7805 input.
Will this work?

Can I use a simple LM7805 for my beeper hobby circuit that monitors a 30V battery ?
The load current doesn't exceed 50mA
It seems the IC will dissipate (30-5)*50mA = 1.25W.
Will the IC survive?

Appreciate simple alternatives to convert 30V to 5V 50mA...

One idea:
I have a lot of 16V 47uF capacitors.
So can I put two 16V capacitors in series and connect the combination to 30V supply in parallel.
Then take the output 15V from the middle and feed it to LM7805 input.
Will this work?

Can I use a simple LM7805 for my beeper hobby circuit that monitors a 30V battery ?
The load current doesn't exceed 50mA
It seems the IC will dissipate (30-5)*50mA = 1.25W worst case.
Will the IC survive?

(As of now I'm using a buck converter and it's taking lot of space; since the load is just 50mA, I realized I could simply use a linear regulator instead)

Appreciate simple alternatives to convert 30V to 5V 50mA...

One idea:
I have a lot of 16V 47uF capacitors.
So can I put two 16V capacitors in series and connect the combination to 30V supply in parallel.
Then take the output 15V from the middle and feed it to LM7805 input.
Will this work?