Timeline for Question about purely resistive incandescent lamps put in series and fed double normal voltage
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 22, 2019 at 17:24 | comment | added | Harper - Reinstate Monica | @G36 it was as linear as Edison could make it. Edison had to, at all costs, develop a bulb that worked in constant voltage, and avoid CC mode, since Tesla had the corner on that tech. | |
| Dec 22, 2019 at 16:00 | answer | added | Tony Stewart EE75 | timeline score: 1 | |
| Dec 22, 2019 at 15:28 | comment | added | AnalogKid | First, calculate the equivalent operating resistance of each lamp using Watt's Law. Then connect them in series in various combinations, use Ohm's Law to calculate the current through the string, and then use Joule's Law to calculate the power dissipated in each resistor. | |
| Dec 22, 2019 at 15:00 | comment | added | G36 | Also in the real-life resistance of an incandescent lamp is not constant. But will changes with the apply voltage (the resistance of a bulb is nonliear). | |
| Dec 22, 2019 at 14:56 | comment | added | G36 | Google the voltage divider, also notice that 60 watts bulb will have a resistance \$R_{60W} = \frac{120V^2}{60W} = 240 \Omega\$ and 40W one will have \$R_{40W} = \frac{120V^2}{40W} = 360 \Omega\$ | |
| Dec 22, 2019 at 14:51 | history | asked | David | CC BY-SA 4.0 |