commit | 95adb9f374a1cca5efda08d20d9fc58d955d4a42 | [log] [tgz] |
---|---|---|
author | Philipp Hagemeister <phihag@phihag.de> | Wed Nov 11 19:58:55 2015 |
committer | Philipp Hagemeister <phihag@phihag.de> | Wed Nov 11 19:58:55 2015 |
tree | 3b4ac4f305e2939555b0e134efe1ba29a9599634 | |
parent | 1cc2f8d82b4a096295c32cd8c5c853cc05d348fa [diff] |
release 1.0.15
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
Note that as in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?