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How to calculate the solubility product for PbS from galvanic potential?
Knowing that at 25 °C the following galvanic cell:
$$\ce{Pb~|~Pb(NO_3)_2~1M~||~PbS~saturated~|~Pb}$$ shows an $\mathrm{EMF} =0.413~\mathrm{V}$, find the $K_\mathrm{sp}$ of $\ce{PbS}$.
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