In my NCERT textbook, in the chapter 'The d- and f-block elements', the last paragraph under oxides and oxoanions of metals goes like this:
$(...)$ $\ce{V2O5}$ is, however, amphoteric though mainly acidic and it gives $\ce{VO4^3-} \space\text{&}\space\ce{VO2+}$ salts (...)
What do they actually mean by the phrase amphoteric though mainly acidic?
Wikipedia clearly states that,
Vanadium(V) oxide (vanadia) is the inorganic compound with the formula $\ce{V2O5}$. Commonly known as vanadium pentoxide, it is a brown/yellow solid, although when freshly precipitated from an aqueous solution, its colour is deep orange. Because of its high oxidation state, it is both an amphoteric oxide and an oxidizing agent. From the industrial perspective, it is the most important compound of vanadium, being the principal precursor to alloys of vanadium, and is a widely used industrial catalyst.
$\ce{V2O5}$ has more of an acidic character than a basic character, doesn't it? How does amphotericity exactly work in practice for vanadium (V) oxoions? Is it difficult to make $\ce{VO2+}$?