Is there any trend here at all? This seems very chaotic as a trend.
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3$\begingroup$ This paper may help. $\endgroup$– DHMOCommented Jan 18, 2017 at 13:27
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3$\begingroup$ It has the common zig-zag practically all properties of alkylic homologues show, and there is a minimum at 5. Looks very regular to me. No.5 cannot decide if it's rather polar or nonpolar, and gets so confused it does not crystallise. $\endgroup$– KarlCommented Jan 18, 2017 at 18:02
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1$\begingroup$ More to the point the odd number carbons have one trend and the even another. $\endgroup$– MaxWCommented Feb 18, 2017 at 6:30
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2 Answers
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My guess without looking at any literature:
Higher acidity $\implies$ higher hydrogen bonding $\implies$ higher melting point.
Thus, changing from H and Me where there is virtually no +I effect from the chain, to Et, Pr, Bu where the +I effect of the chain decreases the melting point, as the hydrogen bonds get weaker, as the COOH groups are less acidic.
Further increasing the chain length after hexyl does not really lead to any additional +I effects on the COOH group that is now far away. Thus, the melting point increases as there are additional van der Waals interactions between the longer chains.
Then there seems to be a factor that makes crystals of odd chains more favorable.
answered Jan 18, 2017 at 14:00
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$\begingroup$ So there are basicall two opposing trends: longer chains decrease the stability of the coo- anion but then after a certain chain length each methylene group adds additional vdw interactions. $\endgroup$ Commented Jan 18, 2017 at 14:02
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$\begingroup$ Please, use proper punctuation, spacing, and capitalization, and do not use short forms unless in chemical formulas. $\endgroup$– DHMOCommented Jan 18, 2017 at 14:05
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$\begingroup$ @DHMO Sorry, was kind of in a hurry ; ) $\endgroup$ Commented Jan 18, 2017 at 18:09
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$\begingroup$ I'm afraid only last 2 sentences are OK to have them in answer to this question. $\endgroup$– MithoronCommented Jan 18, 2017 at 19:37
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An obvious rule is that for even $n+1$ the melting point of the acid $\ce{C_{n+1}}$ is higher than the melting point of acid $\ce{C_n}$.
answered Jan 18, 2017 at 19:40
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1$\begingroup$ I don't find it obvious. Can you explain why? $\endgroup$– YashasCommented Mar 28, 2017 at 12:58
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$\begingroup$ The zigzag line in the above image shows that the melting point increases from 1 to 2, from 3 to 4, from 5 to 6, and so on. I'm quite sure that there's no exception from this rule for n-alkyl carboxylic acids. $\endgroup$ Commented Mar 28, 2017 at 20:57