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Dec 29, 2017 at 0:21 history tweeted twitter.com/StackChemistry/status/946536588737212417
Dec 28, 2017 at 13:32 answer added Nilay Ghosh timeline score: 6
Dec 28, 2017 at 11:46 history edited orthocresol CC BY-SA 3.0
I2- is a little confusing in the title as it could be either iodide(2−) or diiodide(1−)
Dec 28, 2017 at 11:35 history edited Martin - マーチン CC BY-SA 3.0
Substituted picture with MathJax
Dec 28, 2017 at 11:33 comment added andselisk It seems like it does (+refs 1-7 therein).
Dec 28, 2017 at 11:32 comment added Martin - マーチン Probably not, is assume that the equilibrium is entirely on the right side: $\ce{2I2- <=> I- + I3-}$
Dec 28, 2017 at 11:29 review First posts
Dec 28, 2017 at 12:02
Dec 28, 2017 at 11:29 history asked user56884 CC BY-SA 3.0