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    $\begingroup$ Probably not, is assume that the equilibrium is entirely on the right side: $\ce{2I2- <=> I- + I3-}$ $\endgroup$ Commented Dec 28, 2017 at 11:32
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    $\begingroup$ It seems like it does (+refs 1-7 therein). $\endgroup$
    – andselisk
    Commented Dec 28, 2017 at 11:33