Timeline for How many d-electrons are in the outer shell of metals like Cadmium (this is counting the 4d electrons)?
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| Feb 20, 2017 at 10:40 | answer | added | Jan | timeline score: 2 | |
| Feb 16, 2017 at 13:53 | comment | added | jonsno | Most often it is the valence electron which takes part in formation of ionic compounds, even in transition metals. So Yes $[Kr] 4d10$ is correct. | |
| Feb 16, 2017 at 10:07 | comment | added | lalalalala | Thank you! I suspect that because Cd has a +2 charge, the 5s2 electrons will be lost. So in CdS the electron configuration of Cd is [Kr] 4d10. But I didn't know this was possible... I think i've just made up that I can remove the 5s2 electrons in compounds like this. | |
| Feb 16, 2017 at 10:05 | comment | added | airhuff | Hello and welcome to Chemistry.SE! At this point I recommend that you take the short tour to better familiarize yourself with the site. Also, as this appears to be a homework type of question, you should read through this discussion. Regarding your question, which answers do you suspect are correct and why? | |
| Feb 16, 2017 at 10:01 | review | First posts | |||
| Feb 16, 2017 at 10:05 | |||||
| Feb 16, 2017 at 9:58 | history | asked | lalalalala | CC BY-SA 3.0 |