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  • $\begingroup$ Hello and welcome to Chemistry.SE! At this point I recommend that you take the short tour to better familiarize yourself with the site. Also, as this appears to be a homework type of question, you should read through this discussion. Regarding your question, which answers do you suspect are correct and why? $\endgroup$
    – airhuff
    Commented Feb 16, 2017 at 10:05
  • $\begingroup$ Thank you! I suspect that because Cd has a +2 charge, the 5s2 electrons will be lost. So in CdS the electron configuration of Cd is [Kr] 4d10. But I didn't know this was possible... I think i've just made up that I can remove the 5s2 electrons in compounds like this. $\endgroup$
    – lalalalala
    Commented Feb 16, 2017 at 10:07
  • $\begingroup$ Most often it is the valence electron which takes part in formation of ionic compounds, even in transition metals. So Yes $[Kr] 4d10$ is correct. $\endgroup$
    – jonsno
    Commented Feb 16, 2017 at 13:53