The density of a gas $\ce{X}$ is $10$ times that of hydrogen. In that case, what is the molecular weight of gas $\ce{X}$?

Well what I've done up to now is this:

The molecular mass of hydrogen is $M(\ce{H2})=2$, the density of hydrogen is $\rho(\ce{H2}= \pu{0.089 kg/m3}$. Assuming that equal volumes $V$ of both gases are taken, the mass of hydrogen $m(\ce{H2})= (0.089 \cdot v) \pu{kg}$ and the mass of the unknown gas $m(\ce{X}) = (0.89 * v) \pu{kg}$.

Although this hasn't really gotten me anywhere. How will it be done?

The density of a gas $\ce{X}$ is $10$ times that of hydrogen. In that case, what is the molecular weight of gas $\ce{X}$?

Well what I've done up to now is this:

The molecular mass of hydrogen is $M(\ce{H2})=2$, the density of hydrogen is $\rho(\ce{H2})= \pu{0.089 kg/m3}$. Assuming that equal volumes $V$ of both gases are taken, the mass of hydrogen $m(\ce{H2})= (0.089 \cdot v) \pu{kg}$ and the mass of the unknown gas $m(\ce{X}) = (0.89 \cdot v) \pu{kg}$.

Although this hasn't really gotten me anywhere. How will it be done?

It's given that the density of a gas(X) is 10 times that of hydrogen. In that case, what is the molecular weight of gas X?

Well what I've done up to now is this:

molecular mass of hydrogen=2
density of hydrogen= 0.089 kg/m3

Assuming that equal volumes(v) of both gases are taken,
mass of hydrogen = (0.089 * v) kg
mass of gas X = (0.89 * v) kg

Although this hasn't really gotten me anywhere. How will it be done?

The density of a gas $\ce{X}$ is $10$ times that of hydrogen. In that case, what is the molecular weight of gas $\ce{X}$?

Well what I've done up to now is this:

The molecular mass of hydrogen is $M(\ce{H2})=2$, the density of hydrogen is $\rho(\ce{H2}= \pu{0.089 kg/m3}$. Assuming that equal volumes $V$ of both gases are taken, the mass of hydrogen $m(\ce{H2})= (0.089 \cdot v) \pu{kg}$ and the mass of the unknown gas $m(\ce{X}) = (0.89 * v) \pu{kg}$.

Although this hasn't really gotten me anywhere. How will it be done?