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Chemistry

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  • $\begingroup$ All that is needed is that the wavefunctions overlap. If they only do a little then FC factor is small and vice versa. Its the area under the curve of the product that matters, $| \int \psi_i\psi_fdx |^2$ for initial $i$ and final $f$ states. At the time of absorption the molecule can be at any position determined by the probability given by the wavefunction. As you can see the displacement between electronic states is important as to which levels have biggest FC but this is accounted for in the wavefunctions anyway. $\endgroup$
    – porphyrin
    Commented Jun 12 at 18:03