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Apr 19, 2023 at 12:33 comment added Waylander If you have an OH group the proton is quite likely to transfer to the incoming nucleophile and inactivate it.
Apr 19, 2023 at 11:54 comment added raptorlane I see that 2 negative charges by two oxido substituents would create repulsion and is therefore energetically disfavoured. Oxiodo can be protonated to form hydroxide OH. Mechanistically I would expect that OH is attached to the molecule when F- leaves and is therefore present for a specific amount of time. Silylprotecting groups are usually cleaved by fluoride, which is a side product of the reaction. But for the next reactions I indeed plan to mask the oxido unit.
Apr 19, 2023 at 11:26 comment added Waylander You are trying to get a -ve charged (or at least electron-rich) nucleophile to approach an already -ve charged molecule. Can you put a protecting group on the O- species, maybe silyl?
Apr 19, 2023 at 11:15 history edited raptorlane CC BY-SA 4.0
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Apr 19, 2023 at 11:11 history edited raptorlane CC BY-SA 4.0
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Apr 19, 2023 at 11:10 history edited raptorlane CC BY-SA 4.0
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S Apr 19, 2023 at 11:08 review First questions
Apr 19, 2023 at 14:29
S Apr 19, 2023 at 11:08 history asked raptorlane CC BY-SA 4.0