Skip to main content

You are not logged in. Your edit will be placed in a queue until it is peer reviewed.

We welcome edits that make the post easier to understand and more valuable for readers. Because community members review edits, please try to make the post substantially better than how you found it, for example, by fixing grammar or adding additional resources and hyperlinks.

15
  • 3
    $\begingroup$ It is always good to summarize and/or complement the verbal description by algebra. Good practice is starting with symbolic algebraic expressions and keeping it this way until all is ready to plug in literal numbers. It helps in focusing on principles, mistakes are easier to spot, orientation is improved, Q/A is reusable and has bigger permanent value. You may find useful formatting mathematical/chemical expressions/formulas. $\endgroup$
    – Poutnik
    Commented Jan 8, 2023 at 16:51
  • 1
    $\begingroup$ If the correct answer is d) the volume of methanol is 5 L not 5mL. And that is the volume of the liquid so no calculations using the gas equation are relevant to it. $\endgroup$
    – matt_black
    Commented Jan 8, 2023 at 18:16
  • 1
    $\begingroup$ @Natalie Methanol at 20 deg C is liquid, not gas, and you cannot use for it the ideal gas state equation. (attempt 2 ) $\endgroup$
    – Poutnik
    Commented Jan 8, 2023 at 20:01
  • 1
    $\begingroup$ Your first calculation was right. The volume of $\ce{H2}$ must be nearly $9$ L, and not nearly $5$ L. $5$ L is not far from the expected volume of $\ce{CO}$. $\endgroup$
    – Maurice
    Commented Jan 9, 2023 at 19:45
  • 1
    $\begingroup$ @Karl This question is from a past paper of a Chemistry Olympiad test. You’re right I don’t think they considered how practical this question is. $\endgroup$
    – Jane902
    Commented Jan 10, 2023 at 4:01